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tiny-mole [99]
3 years ago
12

NeNe tripled a cookie recipe for a party. The original recipe called for 4.25 cups of sugar. NeNe tripled the sugar amount and p

oured it into a mixing bowl. The mixing bowl got knocked over and 3.46 cups of sugar spilled. How many cups of sugar were left in the mixing bowl?
Mathematics
2 answers:
Tema [17]3 years ago
4 0

Answer:


Step-by-step explanation:

9.29

Nastasia [14]3 years ago
3 0
4.25*3 = 12.75-3.46 = 9.29 cups of sugar left.
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Write an equation for the line that passes through the points (0, -6) and (-3, 0).
Dmitry [639]

Answer:

\displaystyle y = -2x -6

Step-by-step explanation:

x-intercept → Plug in 0 for <em>y</em><em> </em>to get −3 for <em>x</em>

y-intercept → When <em>x</em><em> </em>is set equal to 0 [(0, −6)]

I am joyous to assist you anytime.

3 0
3 years ago
GIVING BRAINLIEST ONCE AGAIN
Andru [333]

Answer:

45

Step-by-step explanation:

divide 25 by 5 to see how they got that, which is 5. then multiply 9 by 5 bc you have to do the same thing, which is 45.

3 0
3 years ago
Read 2 more answers
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
Solve for y:<br> x + 2y = -8<br><br> y=-1/2x+4<br> y=-1/2x-4<br> y=-2x - 4<br> y=1/2x-4
adelina 88 [10]

Answer:

x + 2y = -8 = y = -4 - 1/2x

y= -1/2x + 4 =  y = 4

y= -1/2x - 4 = y = -4

y=-2x - 4 = y = -4

y=1/2x-4 = y = -4

Step-by-step explanation:

(x + 2y = -8 = y = -4 - 1/2x)

x+2y=-8\\2y=-8-x\\y=-4-\frac{1}{2}x\\

4 0
3 years ago
Is 0.15 greater than 1.3
eduard

Answer:

No

Step-by-step explanation:

No because you have to look at the ones first

5 0
3 years ago
Read 2 more answers
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