Two numbers have an absolute value of 37. Which of the two number is farther from 1 on the number line

Mathematics

2 answers:

valentina_108 [34]3 years ago

8 0

The absolue valor of 37 is 37

Brrunno [24]3 years ago

3 0

If I understand what you're saying. It would be the absolute value of -37, which is 37. Also, the absolute value of 37 is 37.

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Can anyone help me out plz and thank you

BARSIC [14]

Wsg is it asking for

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3 years ago

Convert the unit. of length

Sergio [31]

Answer:

Step-by-step explanation:

<em>thats all i got sorry if thats wrong but i hope this helps.</em>

4 0

2 years ago

Need Help help me plz ;(

omeli [17]

So in order to solve you must first combine like terms.
-2y + 2y + 3 = 3
0 + 3 = 3
Subtract 3.
0 = 0
The answer is infinate solution because both numbers are the same.
I hope this helps love! :)

7 0

3 years ago

6) the circular base of a hemisphere of radius 2 rests on the base of a square pyramid of height 6. the hemisphere is tangent to

Rasek [7]

The length of the square base is thus $2 x 3\sqrt{2}/2 = 3\sqrt{2}$ = A

<h3>What is hemisphere?</h3>

Consequently, a hemisphere is a 3D geometric object that is made up of half of a sphere, with one side being flat and the other being a bowl-like shape. It is created by precisely cutting a spherical along its diameter, leaving behind two identical hemispheres.

EXPLANATION; Let ABCDE be the pyramid with ABCD as the square base. Let O and M be the center of square ABCD and the midpoint of side AB respectively. Lastly, let the hemisphere be tangent to the triangular face ABE at P.

Notice that triangle EOM has a right angle at O. Since the hemisphere is tangent to the triangular face ABE at P, angle EPO is also 90 degree. Hence, triangle EOM is similar to triangle EPO.

OM/2 = 6/EP

OM = 6/EP x 2

OM = $6\sqrt{6^2 - 2^2} x 2 = 3\sqrt{2}/2}$