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Bezzdna [24]
3 years ago
6

Find the distance between each point (3,-5),(-3,0)

Mathematics
2 answers:
Elis [28]3 years ago
3 0

Answer:

(-6,5)

Step-by-step explanation:

Allisa [31]3 years ago
3 0

Answer:The answer is (-6,5)

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3
Dvinal [7]

Answer:

ans : x in terms of p is 15/p and if p is -5 than x= -3

Step-by-step explanation:

4( px +1 ) = 64

( Px + 1 ) = 64/4

px = 16 - 1

x = 15/p

and , if p= -5 than,

x = 15 / (-5)

= - 3

4 0
3 years ago
Suppose that y varies directly with x and y=10 when x=8. What is x when y=30? Be sure to simplify your answer.
Naddik [55]
It would be (x) 8*3=24 since (y)10*3=30

so x=24

hope this helps!
8 0
4 years ago
Jessica feeds her dog 3/4 pounds of dog food for each meal. Jessica has just bought 24 pounds of dog food. For how many meals wi
Leokris [45]
To calculate how many meals the dog food would last, we need to multiply 24 by 3/4, since 3/4 pounds is how much dog food the dog eats every meal. 

24 * 3/4 
= 18

Answer: 18 meals

Hope this helped!
4 0
3 years ago
paul a dentist determined that the number of cavities that develops in his patients mouth each year varies inversely to the numb
alex41 [277]

Answer:

Lori will have 1 cavity if she brushed for 120\ sec each night.

Step-by-step explanation:

As the question suggests cavities developed varies inversely with the number of seconds spent on brushing.

Lets take the terms as c=\frac{k}{t},where k is the constant of proportionality.

And

c = Number of cavities developed each year

t = Number of minutes spent on brushing per night

Now we will plugging the values of the given terms and find the value of k,for this we can re-arrange it as...k=c\times( t)

t=30\ sec=\frac{30}{60} =0.5\ min and c=4

k=0.5\times 4=2

Now as Lori will increase her brushing time so as the cavity will decrease.

So for this we have been given,t=120\ sec=\frac{120}{60} = 2\ min and k=2.

As c=\frac{k}{t} =\frac{2}{2} =1

So as per Paul's observation if Lori brushed for 2\ mins at night she will have 1 cavity on that year.

7 0
3 years ago
Read 2 more answers
An open box is constructed of 3500 cm2 of cardboard. The box is a cuboid, with height hcm and square base of side xcm. What is t
erica [24]

Answer:

34.16 cm

Step-by-step explanation:

side of square base = x

height = h

area, A = 3500 cm^2

Area = x² + 4xh = 3500

4 xh = 3500 - x²

h = (3500 - x²)/4x

Volume = Area of base x height

V = x² h

V = x² (3500 - x²)/4x

V = (3500 x - x³) / 4

Differentiate volume with respect to x

dV/dx = (3500 - 3x²) / 4

It is equal to zero for maxima and minima

3500 - 3x² = 0

x = 34.16 cm

Now differentiate again

d²V/dx² = 6x / 4

It is negative so the volume is maximum.

Thus, for x = 34.16 cm, the volume is maximum.

7 0
4 years ago
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