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maria [59]
4 years ago
5

Lee is a teacher at a local high school who wanted to assess whether or not dogs physically resemble their owners enough for peo

ple to be able to correctly match a dog to their owner better than if just guessing. Lee, who is also a dog owner, showed pictures of two dogs to her class of 16 students. One photo was of the teacher's dog (Yoda) and the other photo was of a dog the teacher had never met. The students were asked to guess which dog was actually the teacher's. If dogs do not physically resemble their owners, the students would get a correct match with probability 0.50. It turned out that 14 of the 16 students correctly picked out the teacher's dog.
Does it appear that the population proportion of people who can correctly match a dog to their owner (out of two options) is better than just guessing?
Mathematics
1 answer:
frozen [14]4 years ago
3 0

Answer:

The  decision rule is  

Reject the null hypothesis  

The conclusion is  

There is sufficient evidence to conclude that the population proportion of people who can correctly match a dog to their owner (out of two options) is better than just guessing

Step-by-step explanation:

From the question we are told that

   The sample size is n =  16  

   The population proportion =  0.5

   

     The number that of students that picked out the teachers dog is k  =  14

Generally the sample proportion is mathematically represented as

       \^ p  =\frac{k}{n}

=>     \^ p  =\frac{14}{16}

=>     \^ p  = 0.875

The null hypothesis is  H_o :  p = 0.5

The null hypothesis is  H_o :  p >  0.5

Generally the test statistics is mathematically represented as

   z  =  \frac{\^  p  -  p }{\sqrt{ \frac{p(1- p )}{n} }  }

    z  =  \frac{0.875   -  0.50 }{\sqrt{ \frac{0.50 (1- 0.50 )}{16} }  }

    z  = 3

Generally the p-value is mathematically represented as

    p-value  =  P(Z > 3)

From the z table the probability of  Z>3  is mathematically represented as

      P(Z > 3) =  0.0013499

So

   p-value  =  0.0013499

Let  assume the level of significance is  \alpha = 0. 05

Generally from the value  obtained we see that p-value  <  \alpha Hence  

The  decision rule is  

Reject the null hypothesis  

The conclusion is  

There is sufficient evidence to conclude that the population proportion of people who can correctly match a dog to their owner (out of two options) is better than just guessing

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