Question

What is the area of this triangle?

Answer 1

$\text{In the given triangle we can see that the two sides length is 2.7 ft}\\ \text{and 3.4 ft and the angle between them is }40^{\circ}\\ \\ \text{we know that the area of a triangle with given two sides a and b and }\\ \text{the angle between them, C is given by}\\ \\ \text{Area}=\frac{1}{2}ab\sin C\\ \\ \text{so using this formula, the area of the given triangle is}\\ \\ \text{Area}=\frac{1}{2}(2.7)(3.4)\sin(40^{\circ})$

$\Rightarrow \text{Area}=\frac{9.18}{2}\sin(40^{\circ})\\ \\ \Rightarrow \text{Area}=4.59\sin(40^{\circ})\\ \\ \Rightarrow \text{Area}\approx 2.95$

Hence the area of the triangle is approximately 2.95 square feet

Answer 2

Well, you would have to mutiply the length and width and then divide that by 2 to get your area for the triangle