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Rus_ich [418]
3 years ago
10

A middle school football player, Bo, is just learning how to kick field goals. Currently, he only makes 1/3 of his kicks. A numb

er cube is being used to simulate the result of Bo’s kicks where the numbers 1 or 2 represent a made field goal and the numbers 3,4,5, or 6 represent a missed field goal. Use the following 20 trials of rolling a fair number cube to answer each question.
​ 2436 4251 6233 5316 5212

​ 6643 5326 5313 2152 4164

​ 3642 3554 6413 2563 4533

​ 2512 6634 4536 2112 5546

a. The estimate of the probability that Bo makes three or four field goals is .

​b. The estimate of the probability that Bo does not make any field goals is
Mathematics
1 answer:
Zolol [24]3 years ago
8 0

Currently, he only makes 1/3 of his kicks. ... A number cube is being used to simulate the result of Bo's kicks where the numbers 11 or 22

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Choose the correct translation for the following statement. It is at most ten.
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Answer:

x ≤ 10

Step-by-step explanation:

3 0
3 years ago
QUICK EASY 25 POINTS!!
MAVERICK [17]

Answer:

1. leave the radical symbol and don't try to convert it to a decimal form

2. The approximated value differs from the exact solution and doesn't give a true equation.

3. Depending on the case, if she needs a mathematical answer, the exact value should be used, but for more practical applications, the rounded decimal form would be more usable.

Step-by-step explanation:

The step by step solution to the equation:

4x^3=756\\x^3=\frac{756}{4} =189\\x=\sqrt[3]{189} \\x=\sqrt[3]{3^3*7} \\x=3*\sqrt[3]{7}

1.- Exact solution means that if in the final step when solving for x the value of  x^3 is not a perfect cube, one needs to leave it indicated as a radical expression (with the radical symbol).

in our case, the cubic root of 189 is not a perfect cube. The factor form of 189 is: 3^3*7, so there is a perfect cube factor (3^3), but the other factor (7) is a prime number. Therefore 3 can get out of the root, while 7 stays inside.

2.- The equation was solved above, in exact form. Now to solve it giving a decimal approximation, we use a calculator to find the cubic root of 7, which is an irrational number with infinite number of decimals, the first of which we type here: \sqrt[3]{7} = 1.91293118...

Therefore, the decimal approximation to the solving for x would be:

x=3*\sqrt[3]{7}=3*1,91293118...=5.73879...=5.74

Where we rounded to two decimals as requested.

When we replace the exact answer in the original expression, we get a perfect equality:

4*x^3=756\\4* (3\sqrt[3]{7} )^3=756\\4*3^3*(\sqrt[3]{7} )^3=756\\4*27*7=756\\\\756=756

While if we use the approximate answer, we get:

4*x^3=756\\\\4*(5.74)^3=756\\\\4*189.119224=756\\756.476896=756

which is NOT a true equality.

3.- I would stick with the idea of showing the exact answer as answer to the mathematical equation. but for a practical case (for example she needs to by some material as a result of her equation solving, it would be more practical to take the numerical approximation to the store, instead of a cubic root of a number.

7 0
3 years ago
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strojnjashka [21]
Surface area of box=1200 cm² 
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<span>s = side of square base </span>
<span>h = height of box </span>
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<span>S.A. = surface area or 1200 cm², s²
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<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>


<span>v(s) = s²((1200 - s²)/(4s)) </span>
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by derivating
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again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>


<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
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<span>v = 6000 - 2000 
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Valentin [98]
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7 0
3 years ago
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Answer:

the bridge holds one ton. on Edgunuity

Step-by-step explanation:     <3

4 0
3 years ago
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