Find the quotient when x2 + 10x + 21 is divided by x + 7
1 answer:
<h3>Answer: x+3</h3>
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Work Shown:
x^2+10x+21 factors to (x+3)(x+7) since
7+3 = 10 and 7*3 = 21
Or you can use the FOIL rule to see that (x+3)(x+7) expands to x^2+10x+21
When we divide x^2+10x+21 over x+7, we get,
a pair of (x+7) terms cancel out when we divide
The quotient is x+3
The remainder is 0
See the diagram below for the long division table
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Answer:
The function touches the damping factor
at x= and x=
The x-intercept of f(x) is
at x=
Step-by-step explanation:
Given function is f(x)= and damping factor as y=
and y=
To find when function touches the damping factor:
For f(x)= and y=
Equating the both the equation,
x=
For f(x)= and y=
Equating the both the equation,
x=
Therefore, The function touches the damping factor x= and x=
To find x-intercept of f(x):
For x-intercept, y=0
f(x)=
y=
Hence, is always greater than zero.
Therefore,
x=
Thus,
The x-intercept of f(x) is at x=
