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svet-max [94.6K]
3 years ago
9

PLZZZ HELP!

Mathematics
1 answer:
Helga [31]3 years ago
8 0

bought for $180000 in 2002

sold it in 2014

180000*2.44\100

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Item 7 you and a friend are running on treadmills. you run 0.5 mile every 3 minutes, and your friend runs 2 miles every 14 minut
sweet [91]
<span>You run 0.5 miles every 3 minutes => 1 mile every 6 minutes. Your friend runs 2 miles every 14 minutes => 1 mile every 7 minutes. You run a whole number of miles every number of minutes that is a multiple of 6. Your freind runs a whole number of miles every number of minutes that is a multiple of 7 Then the least possible number of miles that you both run to end at the same time is the least common factor of 7 and 6 minutes. This is 7 * 6 = 42 minutes. You will have run 42 min / (6 miles/min) = 7 miles, and your friend will have run 42 min / (7 miles/min) = 6 miles</span>
5 0
3 years ago
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Which formula should be used to calculate the amount of paper needed?
bogdanovich [222]

Answer:

Step-by-step explanation:

I=PRT where I =interest P=principal, R=rate, and T =time is

3 0
3 years ago
PLEASE HELP ME I CANT FAIL THIS CLASS
ale4655 [162]

Answer:

It would be the first answer.

Step-by-step explanation:

y=-2x^2+4x-2

y=-2(-1)^2+4(-1)-2

y=-2(1)-4-2

y=-2-4-2

y=-6-2

y=-8

(-1,-8)

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4 0
3 years ago
A polygon has its vertices at the following points.
seropon [69]

Answer:

isosceles trapezoid

Step-by-step explanation:

1) find the distance of the points

\sqrt{(x2-x1)^2 + (y2 -y1)^2}

AB = \sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}

BC = |7-4| = 3

CD = \sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}

AD = |9-2| = 7

2) equation of the line that passes threw BC

y = 7

3) equation of the line that passes threw AD

y = 5

conclusion

the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid

3 0
2 years ago
Ratio Question;
SashulF [63]

*Given

Money of Phoebe            - 3 times as much as Andy

Money of Andy                - 2 times as much as Polly

Total money of Phoebe,  - £270

   Andy and Polly

*Solution

Let

B - Phoebe's money

A - Andy's money

L - Polly's money

1. The money of the Phoebe, Andy, and Polly, when added together would total £270. Thus,

                 B + A + L  = £270                     (EQUATION 1)

2. Phoebe has three times as much money as Andy and this is expressed as

 

                 B = 3A

3. Andy has twice as much money as Polly and this is expressed as

                 A = 2L                           (EQUATION 2)

4. This means that Phoebe has ____ as much money as Polly,

                B = 3A

                B = 3 x (2L)

                B = 6L                            (EQUATION 3)

This step allows us to eliminate the variables B and A in EQUATION 1 by expressing the equation in terms of Polly's money only.

5. Substituting B with 6L, and A with 2L, EQUATION 1 becomes,

                 6L + 2L + L = £270

                               9L = £270

                                 L = £30

So, Polly has £30.

6. Substituting L into EQUATIONS 2 and 3 would give us the values for Andy's money and Phoebe's money, respectively.

                 A = 2L                          

                 A = 2(£30)

                 A = £60

Andy has £60

                 B = 6L                        

                 B = 6(£30)

                 B = £180

Phoebe has £180

Therefore, Polly's money is £30, Andy's is £60, and Phoebe's is £180.

3 0
3 years ago
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