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Leokris [45]
3 years ago
15

Please help me!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
RSB [31]3 years ago
4 0

Answer:

Blobfish

Step-by-step explanation:

Never

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Select the correct solution set. 50 ≥ 15x
Leviafan [203]
50 > = 15x....divide both sides by 15
50/15 > = x
10/3 > = x or x < = 10/3

so the correct solution set is : { x | x < = 10/3}...its the 2nd one
6 0
4 years ago
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In △JKL, solve for x. <br><br> (A)74.89<br> (B)30.29<br> (C)38.16<br> (D)66.73
Stels [109]

ANSWER

(C)38.16

EXPLANATION

The acute angle given in the right triangle is 27°.

The side length adjacent to the 27° angle is 34 units.

The side length we want to find is x units, which is the hypotenuse of the right triangle.

We use the cosine ratio to obtain:

\cos(27 \degree)  =  \frac{adjacent}{hypotenuse}

\cos(27 \degree)  =  \frac{34}{x}

Solve for x,

x  =  \frac{34}{\cos(27 \degree)}

x = 38.16

to the nearest hundredth.

4 0
4 years ago
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It is exponent laws what is the answer
Aleonysh [2.5K]
Use all the top to multiply by it Then divide by the buttom.
7 0
3 years ago
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12 girls make uo 48%of a team how manyboys are on the team
Sergeu [11.5K]
12 girls - 48%
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5 0
3 years ago
On a coordinate plane, triangles P Q R and S T U are shown. Triangle P Q R has points (4, 4), (negative 2, 0), (negative 2, 4).
mamaluj [8]

Answer:

The answer is below

Step-by-step explanation:

Two triangles are said to be similar if their corresponding angles are equal and the corresponding sides are in proportion.

The distance between two points on the coordinate plane is given as:

Distance=\sqrt{(x_2-x_1}^2+(y_2-y_1)^2 \\\\Therefore\ in\ triangle\ PQR:\\\\|QR|=\sqrt{(-2-(-2))^2+(4-0)^2}=4\\\\|PQ|=\sqrt{(-2-4)^2+(0-4)^2}=\sqrt{52}=2\sqrt{13}    \\\\|PR|=\sqrt{(-2-4)^2+(4-4)^2}=6

In triangle STU:

|ST|=\sqrt{(-1-2)^2+(-2-(-4))^2}=\sqrt{13}\\\\|SU|=\sqrt{(-1-2)^2+(-4-(-4))^2}  =3\\\\|TU|=\sqrt{(-1-(-1))^2+(-4-(-2))^2}=2

|QR| / |TU| = 4/2 = 2

|PR| / |SU| = 6/3 = 2

|PQ| / |ST| = 2√13 / √13 = 2

Hence:

|QR| / |TU| = |PR| / |SU| = |PQ| / |ST|

Therefore, △PQR and △STU are similar triangles since the ratio of their sides are in the same proportion.

6 0
3 years ago
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