The experimental probability is C. 17%.
17% is derived from the following solution.
14/84 = 0.1666
0.1666 * 100% = 16.66% or 17%
This is based on the result of the experiment conducted.
The theoretical probability of A is 20%.
1/5 = 0.20
0.20 x 100% = 20%
A is only one event out of 5 letters.
Answer:
other side is 12
Step-by-step explanation:
Givens
Perimeter = 64 feet
L = 20
Formula
P = 2L + 2w Substitute Givens
64 = 2*20 + 2w Combine
64 = 40 + 2w Subtract 40 from both sides
64-40 = 40-40+2w Combine
24 = 2w Divide both sides by 2
24/2=2w/2
12 = w
(18-x)-4+9 I’m pretty sure this is correct
1) since its pairs your working with what you do is y2-y1 and x2-x1 so to start its 9-(-2) which equals 11 then -4-(-3) which equals -1, 11/-1 is -11 I hope this is helpful . . .
2) to start its y=mx+b so since your slope is 2 and your pair is (0,-3) the equation would be -3=2(0)+b since 2(0) equals 0 your left with -3=0+b subtract 0 over answers b=-3
Answer:
<h2><em>
2ft by 2ft by 1 ft</em></h2>
Step-by-step explanation:
Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;
S = lw+2wh+2lh ... 1
Given the volume V = lwh = 4ft³ ... 2
From equation 2;
h = 4/lw
Substituting into r[equation 1;
S = lw + 2w(4/lw)+ 2l(4/lw)
S = lw+8/l+8/w
Differentiating the resulting equation with respect to w and l will give;
dS/dw = l + (-8w⁻²)
dS/dw = l - 8/w²
Similarly,
dS/dl = w + (-8l⁻²)
dS/dw = w - 8/l²
At turning point, ds/dw = 0 and ds/dl = 0
l - 8/w² = 0 and w - 8/l² = 0
l = 8/w² and w =8/l²
l = 8/(8/l² )²
l = 8/(64/I⁴)
l = 8*l⁴/64
l = l⁴/8
8l = l⁴
l³ = 8
l = ∛8
l = 2
Hence the length of the box is 2 feet
Substituting l = 2 into the function l = 8/w² to get the eidth w
2 = 8/w²
1 = 4/w²
w² = 4
w = 2 ft
width of the cardboard is 2 ft
Since Volume = lwh
4 = 2(2)h
4 = 4h
h = 1 ft
Height of the cardboard is 1 ft
<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>
