Answer:
a) x = 1 + t
y = 3 - t
z = 8 +2t
b) In XY plane (-3,-1,0)
In YZ plane (0, 4, 6)
In XZ plane ( 4,0,14)
Step-by-step explanation:
The equation of plane is given as
x -y +2z = 5
a)
COMPARE THE ABOVE EQUATION with Ax+ By +Cz = d
A = 1, B = -1. C = 2
N = (1,3,8) {GIVEN POINT]
the parametric eqn. of line P(Xo , Yo, Zo) and prependicular plan Ax+ By+ Cz = d is given as
X = Xo+ At
Y = Yo + Bt
Z=Zo + Ct
x = 1 + t
y = 3 - t
z = 8 +2t
b) Line intersecting XY plane if z equal to zero i.e
0 = 8 + 2t
t =-4
for t = -4
x = -3, y = -1, z = 0
In YZ plane, x = 0
t = -1
interesting point will be
(0, 4, 6)
In XZ plane, Y = 0
t = 3
interesting point will be
(4, 0, 14)
Step-by-step explanation:
i thik 12.92 not sure.............☺️
The domain is the x-values used by the graph.
The range is the y-values used by the graph.
With respect to the x-axis, the graph starts at 0 on the left and goes as far as x=15.
With respect to the y-axis, the graph starts as low as 0 (vertically) and goes as high as 75.
The range is 0≤x≤15.
The domain is 0≤y≤75.
Answer:
15(2d+1)
Step-by-step explanation:
we are going to multiply the numbers
5 x 6d + 5 x 3
30d + 5 x 3
30d + 15
then we factor out 15 from the expression
15 (2d+1)
