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Igoryamba
3 years ago
15

PLEASE ANSWER QUICK

Mathematics
1 answer:
muminat3 years ago
3 0
I solved the problem, answer is 11.4% as 2500-11.4% is 2215.
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2x-4y=8<br> x+2y=4<br> How many solutions (x, y) are there to the system of equations above? explain
Mekhanik [1.2K]

Answer:

Exactly one solution.

Step-by-step explanation:

2x-4y=8

x+2y=4    /*2

<em>2x-4y=8</em>

<em><u>2x+4y=8 (+)</u></em>

4x=16

x=4

4+2y=4

y=0

(x;y)={(4; 0)}

Exactly one solution.

6 0
4 years ago
HELP PLEASE WITH THIS SOLVING QUADRATIC EQUATION QUICK
liraira [26]

Answer:

11, -4

Step-by-step explanation:

x =  \frac{ - b +  \sqrt{ {(b)}^{2} + - 4(a)(c) } }{2a}

x =  \frac{ - b  -   \sqrt{ {(b)}^{2} + - 4(a)(c) } }{2a}

you have to do both of these top equations

a = 1

b = -7

c = -34 - 10 = -44

substitute these numbers into both equations to get x

x = 11 , -4

3 0
3 years ago
Solve for x im not good at math
REY [17]

the answer would be x=9

4 0
3 years ago
Read 2 more answers
Randomly split the messages into a training set D1 (80% of messages) and a testing set D2 (20% of messages). Calculate the testi
Blizzard [7]

Answer:

In the step-by-step

Step-by-step explanation:

This is the code i created using the R software and the packages "caret" and "e0171".

The script was supposed to work in all general cases.

library(caret)

library(e1071)

# Categorical vector

spam <- c("spam","not_spam")

spam_vec <- sample(spam,60, replace = T)

# Supposing two independent variables so that the kappa will be close to 0.

x1 <- rnorm(60)

x2 <- rnorm(60)

# Creating the dataset

data1 <- cbind(spam_vec,x1,x2)

data1 <- as.data.frame(data1)

names(data1) <- make.names(c("spamvec","x","y"))

# Creating the partition

index <- createDataPartition(data1$spamvec,

                            p=0.8, list=FALSE)

training_data <- data1[index,]

testing_data <- data1[-index,]

fitControl <- trainControl(method = "cv",

                         number = 5,

                         savePred = TRUE,

                         classProb = TRUE)

tune.grid <- expand.grid(C = seq(0, 10, .1))

# Scaling the predictors

preProcess_cs <- preProcess(training_data[, -1],

                                 method = c("center", "scale"))

spam_training_cs      <- predict(preProcess_cs, training_data)

spam_testing_cs       <- predict(preProcess_cs, testing_data)

# Training a Naive Bayes to predict binary outcome

Naive_Bayes_Model=naiveBayes(spamvec ~.,

                            data=spam_training_cs,

                            tuneGrid = tune.grid,

                            trControl = fitControl)

# Confusion matrix

prediction <- predict(Naive_Bayes_Model, spam_testing_cs)

confusionMatrix(prediction, spam_testing_cs$spamvec, positive = "spam")

confM <- confusionMatrix(prediction, spam_testing_cs$spamvec, positive = "spam")

accuracy <- confM$overall[1]

accuracy

3 0
3 years ago
The basketball team practices every day from 2:30 pm to 4:00 pm.todays practice ended 20 minutes early.at what time did basketba
Goshia [24]
3:40 because 4:00 minus 20 is 3:40
8 0
3 years ago
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