Ajutatima la ecuatia q*435=810
1 answer:
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Refer to the diagram shown below.
The dimensions of the outside of the picture rame are:
Width = x + 1 + 1 = x + 2 inches
Length = (x+2) + 1 + 1 = x + 4 inches.
The perimeter of the outside of the picture frame is 28 inches.
Therefore
2(x + 2) + 2(x+4) = 28
Solve for x.
2x + 4 + 2x + 8 = 28
4x + 12 = 28
4x = 16
x = 4 inches
Answer: 4 inches
The dimensions of the outside of the picture rame are:
Width = x + 1 + 1 = x + 2 inches
Length = (x+2) + 1 + 1 = x + 4 inches.
The perimeter of the outside of the picture frame is 28 inches.
Therefore
2(x + 2) + 2(x+4) = 28
Solve for x.
2x + 4 + 2x + 8 = 28
4x + 12 = 28
4x = 16
x = 4 inches
Answer: 4 inches
Answer:
A.
Explanation:
1. You can factor out a 4.
2. Factor .
X-Method:
1. Draw an X
2. Multiply ac (2(-2)=-4) then put it in the top part of the X
3. Then put b, -3, in the bottom part of the X
4. On the two sides of the X find out what added together equals b, -3,
and multiplied equals ac, -4.
5. -4(1)=-4 & -4+1=-3
6. If the quadratic has a coefficient then you must divide the two sides
of the X by that coefficient, 2.
7. -4/2=-2 & 1/2 can't be evenly divided into, so in this case the
coefficient remains.
8. When you write this out it will be (2x+1)(x-2)
3. Put it together to get your answer.