Ajutatima la ecuatia q*435=810
1 answer:
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Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
I used Desmos to graph it but here are the coordinates used to graph it in the pictures below.
<h2>Answer:</h2>
A.) {-6, -2, 5}
<h2>Step-by-step explanation:</h2>A function from a set
to a set
is a relation that assigns to each element
in the set
exactly one element
in the set
. The set
is the domain (also called the set of inputs) of the function. From the figure, we can see that this set is the x-coordinate of each red point. So this set is {-6, -2, 5}