All categories

3 years ago

The sum of 6 consecutive integers is 519. What is the third number in this sequence?

Mathematics

2 answers:

garri49 [273]3 years ago

8 0

The third integer is 86, hope this helps :)

Gekata [30.6K]3 years ago

7 0

Let the third number be n. then the series of numbers is n-2, n-1, n, n+1, n+2, n+3. The sum of these numbers should be 519. Add them together and solve for n:
n-2+n-1+n+n+1+n+2+n+3=519
6n+3=519
6n=516
n=86

So the third number is 86.

You might be interested in

Create a Sample Space diagram and work out the probability - There is a 4 sided dice (numbers 1 to 4) and an 8 sided dice (numbe

tester [92]

Answer:

7 / 16

Step-by-step explanation:

Sample space is attached below :

Theoretical Probability of any event A

P(A) = (number of required outcome / Total number of possible outcomes)

Required outcome = sum greater than 7 = 14

Total number of possible outcomes = 32

P(sum greater than 7) = 14 / 32

P(sum greater than 7) = 7 / 16

3 0

2 years ago

Which of the following represents 3x-5y+10=0 written in slope-intercept form?

taurus [48]

For this case we have that by definition, the equation of a line in the slope-intercept form is given by:

$y = mx + b$

Where:

m: Is the slope

b: Is the cut-off point with the y axis

We have the following equation:

$3x-5y + 10 = 0$

We manipulate algebraically:

We subtract 10 from both sides of the equation:

$3x-5y = -10$

We subtract 3x from both sides of the equation:

$-5y = -3x-10$

We multiply by -1 on both sides of the equation:

$5y = 3x + 10$

We divide between 5 on both sides of the equation:

$y = \frac {3} {5} x + \frac {10} {5}\\y = \frac {3} {5} x + 2$

Thus, the equation in the slope-intercept form is $y = \frac {3} {5} x + 2$

Answer:

$y = \frac {3} {5} x + 2$

5 0

3 years ago

Suppose that a function f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence

Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

$\lim_{x \to c} \frac{x^2-cx}{(x-c)}$

We can simplify it

$\lim_{x \to c} \frac{x(x-c)}{(x-c)}$

$=\lim_{x \to c} x$

$=c$

so, we can see that limit exist and it's value defined

case-2:

$\lim_{x \to c} \frac{1}{(x-c)}$

Left limit is

$\lim_{x \to c-} \frac{1}{(x-c)}$

$=-\infty$

Right Limit is

$\lim_{x \to c+} \frac{1}{(x-c)}$

$=+\infty$

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0

3 years ago

Please help me please help me

Anon25 [30]

Answer:

AM=26

Step-by-step explanation:

Since M is the midpoint of the number line, this means that each side is equal to each other. The midpoint evenly splits it up in half, and since each side is equal that means we can set up an equation making x+20 and 5x-4 the same value.

x+20 = 5x-4

Now you simply carry over, so that x is all by itself. I carried the -4 to the other side first. To carry it over you have to add 4 on both sides, leaving this:

x+24=5x

Then I carried the x to the other side by subtracting -x (or if it helps, imagine an invisible one next to the x so it would be -1x) on both sides.

This gives me: 24=4x

Now that all the x's are by themelves, we can divide 24 by 4 to get our x value:

6=x

Now all we need to do is plug that in for the length of AM:

6+20, which equals our final answer 26

I hope you found this helpful :)

5 0

1 year ago

A carpenter can build a toolshed three times as fast as his apprentice. Working

UkoKoshka [18]

Answer:

Step-by-step explanation:

7 0

2 years ago