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Novosadov [1.4K]
3 years ago
7

Convert 135 seconds into minutes

Mathematics
2 answers:
Elena L [17]3 years ago
8 0

2.25 Minutes is the answer. :)


goldenfox [79]3 years ago
3 0

2 mins and 25 seconds

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Solve 5x^2 - 7x+2 -0 by completing the square. What are the solutions?
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5<em>x</em>² - 7<em>x</em> + 2 = 0

5(<em>x</em>² - 7/5 <em>x</em>) + 2 = 0

5(<em>x</em>² - 7/5 <em>x</em> + 49/100 - 49/100) + 2 = 0

5(<em>x</em>² - 2 • 7/10 <em>x</em> + (7/10)²) - 49/20 + 2 = 0

5(<em>x</em> - 7/10)² - 9/20 = 0

5(<em>x</em> - 7/10)² = 9/20

(<em>x</em> - 7/10)² = 9/100

<em>x</em> - 7/10 = ± √(9/100)

<em>x</em> - 7/10 = ± 3/10

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<em>x</em> = 10/10 = 1   or   <em>x</em> = 4/10 = 2/5

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Derek jeter hit 22 home runs one season. If that was only two-thirty-firsts of all the home runs hit by the yankees, how many ho
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Feel free to ask any questions as to what I did

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1 and 5/8 or 1 and 16/25 which is bigger
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A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current
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Answer:

z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5  

Since is a left sided test the p value would be:  

p_v =P(z  

Comparing the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

Step-by-step explanation:

Data given and notation  

\bar X=7.1 represent the sample mean    

\sigma=1.2 represent the population standard deviation

n=36 sample size  

\mu_o =7.4 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 7.4, the system of hypothesis would be:  

Null hypothesis:\mu \geq 7.4  

Alternative hypothesis:\mu < 7.4  

The statistic is given by

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5  

P-value  

Since is a left sided test the p value would be:  

p_v =P(z  

Conclusion  

Comparing the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

6 0
3 years ago
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