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Ne4ueva [31]
3 years ago
11

Teresa is a civil engineer who uses her automobile for business. Teresa drove her automobile a total of 11,965 miles during 2019

, of which 80% was business mileage. The actual cost of gasoline, oil, depreciation, repairs, and insurance for the year was $6,440. Teresa is eligible to use the actual or standard method. If required, round your answers to the nearest dollar. a. How much is Teresa's transportation deduction based on the standard mileage method? $ b. How much is Teresa's transportation deduction based on the actual cost method? $ c. Which method should Teresa use to calculate her transportation deduction? Since the method yields the larger deduction, Teresa should use the method to determine her deduction.
Engineering
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

a) $5552

b) $5152

c) Since the standard mileage method yields the larger deduction, Teresa should use the standard mileage method to determine her deduction.

Explanation:

a. How much is Teresa's transportation deduction based on the standard mileage method?

Her miles is:

= 11,965 miles * 80%

= \frac{11965 * 80}{100} \\= \frac{957200}{100} \\= 9572

According to the IRS site, the standard mileage rate for 2019 is 58 cent

So, her deduction is:

= 9572 * 58\\= 555176

= 555, 176 cent

To the nearest dollar, we divide by 100:

555176/100 = $5551.76

which is approximately $5552 to the nearest dollar

b. How much is Teresa's transportation deduction based on the actual cost method?

By actual cost, the deduction is:

= 80% * $6440

= \frac{6440 * 80}{100} \\= \frac{515200}{100} \\= 5152

To the nearest dollar, Teresa deduction is $5152

c. Which method should Teresa use to calculate her transportation deduction?

Since the standard mileage method yields the larger deduction, Teresa should use the standard mileage method to determine her deduction.

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Which of the following statements about pitot-static systems is FALSE? a). A pitot probe measures the Total Pressure of the free
Pavlova-9 [17]

Answer:

C

Explanation:

Pitot tube:

  Pitot tube is a device which is used to measure the velocity of flow by measuring pressure difference between the points.

As we know that stagnation pressure is the summation of dynamic and static pressure.

Stagnation pressure = Static pressure + Dynamic pressure

So

Dynamic pressure  = Stagnation pressure -  Static pressure

We know that dynamic pressure

P_{dynamic}=\dfrac{\rho V^2}{2}

On the other hand Pitot tube measure the dynamic pressure.

So option C is correct.

5 0
3 years ago
what are 3 things you would like to get out of an ethical engineering class? and why? about a page explanation would do fine.
poizon [28]

Answer:

I don't know

Explanation:

i don't know

8 0
3 years ago
Read 2 more answers
The objective of a properly proportioned concrete mix are: a.__________________________________________________________ b.______
sukhopar [10]

Answer:

The objective of a properly proportioned concrete mix are:

  • To produce the combination of cementitious material, water, and aggregate that meets the requirements of a particular structure, portion of a structure, or series of structures at least cost.
  • To produce concrete of the specified properties.
  • To produce a satisfactory of end product, such as beam, column or slab as economically as possible.

Cheers!

4 0
3 years ago
Read 2 more answers
One kilogram of water fills a 0.140 m^3 rigid container at an initial pressure of 1.8 MPa. The container is then cooled to 40°C.
Pavel [41]

Answer:

T1 = 299.18 °C

P2 = 0.00738443 MPa

Explanation:

From the data, we can get two properties for the initial condition. These are pressure and specific volume.

The pressure is 1.8 MPa and the specific volume, we can get it with the mass and volume of the container, since it’s filled this is also the volume of the water in it.

v=\frac{vol (m^{3})}{mass (kg)} = \frac{0.140 m^{3}}{1 kg} = 0.140 \frac{ m^{3}}{kg}

When we check in the thermodynamic tables, the conditions for saturation at 1.8 MPa we found the following:

P^{sat} = 1.8 MPa

T^{sat} = 207.12 C

v_{g} = 0.1103\frac {m^{3}}{kg} specific volume for the saturated vapor  

v_{l} = 0.001167 \frac{m^{3}}{kg} specific volume for the saturated liquid  

Since the specific volume in our condition is higher that the specific volume for the saturated vapor, we have a superheated steam.  

Looking in the thermodynamic tables for superheated steam we found that the temperature where the steam has a specific volume of 0.140 \frac{ m^{3}}{kg} at 1.8 MPa is 299.18 °C. This is the initial temperature in the container.

Since the only information that we have about the final condition is that the container was cooled. We can assume that it was cooled until a condition of saturation. So, the final pressure for the water will be the pressure of saturation for a temperature of 40°C. From thermodynamic tables we get:

P^{sat} at 40C = 0.00738443 MPa

7 0
3 years ago
A classroom which normally contains 26 people is to be air- conditioned. A person in the classroom typically dissipates heat at
lutik1710 [3]

Answer:

Explanation:

Heat dissipated by 26 people per second

= 26 x 360 x 1000 / (60 x 60)

= 2600 J

Heat dissipated by bulbs per second

= 15 x 40

= 600 J

Heat dissipated by fans per second

200 J

Heat dissipated by air coming in

= 200 x 10 x 1000 / (60 x 60)

=555.55 J

Heat gain by walls

= 5000 x 1000 / (60 x 60)

= 1388.88 J

Total heat gain per second

= 2600 + 600+200+555.55

= 3955.55 J

Capacity of air-conditioner required

= 3955.55 J/s

= 3.9 kJ/s

= 3.9kW

= 4 kW

7 0
3 years ago
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