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3 years ago

10

If 7 times a number is equal to 7 plus that number which of the following represents the equation needed to determine what that

number is?
a) x+7x=7
b) 7x=7
c) 7+x=7
d) 7x=x+7
e) 7(x+1)=7

1 answer:

HACTEHA [7]3 years ago

8 0

The correct answer would be d
As it states seven times x is equal to x plus 7

GOOD LUCK!
BRAINLIEST?

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3 years ago

What's the next number 2 3 5 7 11 13 17

maw [93]

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3 years ago

Read 2 more answers

What is the equation in standard form of the line Y equals 1 / 9 x + 5

Juli2301 [7.4K]

Answer:

1/9x - y = -5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Algebra I</u>

Standard Form: Ax + By = C

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

<u>Step 1: Define equation</u>

Slope-Intercept Form: y = 1/9x + 5

<u>Step 2: Find Standard Form</u>

Subtract 1/9x on both sides: -1/9x + y = 5
Multiply -1 on both sides: 1/9x - y = -5

4 0

2 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

so

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

Ms. Jones had $40 to purchase groceries. She bought 4 packs of rice and 3 boxes of granola bars. The packs of rice cost $1.09 ea

Nesterboy [21]

Answer:

so to know full price of granola bars and rice packs; you would multiply 1.09 × 4 for the rice which you get 4.36 then for granola bars you do 4.29 × 3 and you get 12.87 then you add 12.87 + 4.36 = 17.23 then you subtract this from the $$ Mr.Jones has which is 40 so its 40-17.23 and you get 22.77

7 0

3 years ago