Answer:
A)196J
B)-208J
C)3467J
Step-by-step explanation:
We are given that a 20 kg cylindrical mass is dropped onto the mat from a height of 1 m above the mat. During the impact, the cylinder’s vertical velocity reaches zero at the instant the mat has compressed to only 4 cm thick.
So, The Mat gets compressed by : 10cm - 4 cm = 6 cm=0.06 m
a)
Using Conservations of energy
Potential energy at the top = Kinetic energy at the point before touching the surface
Kinetic energy = mgh= 
b)
Work done by the mat do to stop the fall of the cylinder =
C)
Work done=

F=3467J
Answer is the second option, the one that says X+1/1
The diagram for m<VSR is 80°
Answer:
-18x+73
Step-by-step explanation:
-9 times 2x is -18x
-9 times -7 is 63
63+10=73
so, -18x+73 is your answer