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Sphinxa [80]
4 years ago
13

Convert 4,500ft/h into ft per second. please

Mathematics
1 answer:
OLga [1]4 years ago
6 0

Answer:

1.25 ft/sec

Step-by-step explanation:

4500 ft/h = 4500 ft/hr x 1 hr/3600 sec = 5/4 ft/sec = 1.25 ft/sec

Please check my other articles in my site, just copy and paste this word to google search engine: learningandassignments diy4pro.

Hope it helps you.

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42×10 minutes in shower
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3 years ago
For f(x)=3x+1 and g(x)=x²-6, find (f-g)(x)
Lorico [155]

The value of (f - g)(x) is -x² + 3x + 7.

<h3>What is Function?</h3>

The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

Here, the given functions are;

   f(x) = 3x + 1

   g(x) = x² - 6

Now,

 (f - g)(x) = f(x) - g(x)

              = (3x + 1) - (x² - 6)

              = 3x + 1 - x² + 6

(f - g)(x)  = -x² + 3x + 7

Thus, the value of (f - g)(x) is -x² + 3x + 7.

Learn more about Function from:

brainly.com/question/12431044

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8 0
2 years ago
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What is 32% of 65?????????????????????????????????????
Inessa05 [86]

Answer:20.8 is the correct answer

Step-by-step explanation:asked Siri

5 0
3 years ago
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The focal length F of a lens made by combining two lenses of focal length U and V is given I/F=I/U+I/V
jolli1 [7]

Answer:

a). V=\frac{U.F}{U-F}

b). V = 15 units

Step-by-step explanation:

Focal length F of a lens made by combining two lenses of different focal lengths U and V will be,

\frac{1}{F}=\frac{1}{U}+\frac{1}{V}

A). By solving the given formula,

    \frac{1}{V}=\frac{1}{F}-\frac{1}{U}

    \frac{1}{V}=\frac{U-F}{U.F}

    V=\frac{U.F}{U-F}

B). If F = 6 and U = 10 then we have to find the value of V.

    By substituting the given values in the formula,

    V=\frac{6\times 10}{10-6}

    V=\frac{60}{4}

    V = 15 units

    Therefore, focal length (V) of the lens = 15 units

4 0
4 years ago
Can you help me with this question
FrozenT [24]
I think , in my opinion it’s is the middle I’m not that sure but if u can try then good luck
5 0
4 years ago
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