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Shalnov [3]
2 years ago
12

What is the value of this expression when a= - 3 and b=-2? (3a^-2b^6/2a^-1b^5)^2

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
7 0

Answer:

so lets just rewrite it with A=-3 amd B=-2

(-9^4^-9^2^5)^2

which is equal to... 1!

Hope This Helps!!!

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X+y=2 8x+3y=-19 substitution
padilas [110]

Answer:

{x,y}={−5,−7}

Explain:

// Solve equation [2] for the variable  y [2]    3y = 7x + 14 [2]    y = 7x/3 + 14/3 // Plug this in for variable  y  in equation [1] [1]    8x - 3•(7x/3+14/3) = -19 [1]    x = -5 // Solve equation [1] for the variable  x [1]    x = - 5 // By now we know this much : x = -5 y = 7x/3+14/3 // Use the  x  value to solve for  y y = (7/3)(-5)+14/3 = -7 Solution : {x,y} = {-5,-7}

Hoped I helped

4 0
3 years ago
Read 2 more answers
Simplify 12x6 y7 18 x3y5.
Ksivusya [100]

Answer:

216x^9y^12

Step-by-step explanation:

5 0
3 years ago
What effect does doubling the radius of a cylinder have on the volume of the cylinder?
BabaBlast [244]
Doubling the radius of the cylinder will quadruple the volume.
3 0
3 years ago
What is the solution of x=2+ square root x-2?
alex41 [277]

So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

x-2=\sqrt{x-2}

Next, square both sides:

(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2

Next, subtract x and add 2 to both sides of the equation:

x^2-5x+6=0

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

x^2-2x-3x+6=0

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

x(x-2)-3(x-2)=0

Now you can rewrite the equation as (x-3)(x-2)=0

Now, apply the Zero Product Property and solve for x as such:

x-3=0\\x=3\\\\x-2=0\\x=2

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>

8 0
3 years ago
Write an equation of the line that passes through (1,2) and is parallel to the line y=-5x+4
valentinak56 [21]

Answer:

The equation of the Parallel line to the given line is  5x+y-7=0

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the line y = - 5x+4 and point (1,2)

The equation of the Parallel line to the given line is  ax+by+k=0

Given straight line  5x + y -4 =0

The equation of the Parallel line to the given line is  5x+y+k=0

This line passes through the point (1,2)

             5x+y+k=0

            5(1)+2+k=0

⇒              7+k=0

                   k =-7

<u>Final answer:-</u>

The equation of the Parallel line to the given line is  5x+y-7=0

7 0
3 years ago
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