Answer:
{x,y}={−5,−7}
Explain:
// Solve equation [2] for the variable y [2] 3y = 7x + 14 [2] y = 7x/3 + 14/3 // Plug this in for variable y in equation [1] [1] 8x - 3•(7x/3+14/3) = -19 [1] x = -5 // Solve equation [1] for the variable x [1] x = - 5 // By now we know this much : x = -5 y = 7x/3+14/3 // Use the x value to solve for y y = (7/3)(-5)+14/3 = -7 Solution : {x,y} = {-5,-7}
Hoped I helped
Answer:
216x^9y^12
Step-by-step explanation:
Doubling the radius of the cylinder will quadruple the volume.
So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

Next, square both sides:

Next, subtract x and add 2 to both sides of the equation:

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
Answer:
The equation of the Parallel line to the given line is 5x+y-7=0
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the line y = - 5x+4 and point (1,2)
The equation of the Parallel line to the given line is ax+by+k=0
Given straight line 5x + y -4 =0
The equation of the Parallel line to the given line is 5x+y+k=0
This line passes through the point (1,2)
5x+y+k=0
5(1)+2+k=0
⇒ 7+k=0
k =-7
<u>Final answer:-</u>
The equation of the Parallel line to the given line is 5x+y-7=0