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Shalnov [3]
3 years ago
12

What is the value of this expression when a= - 3 and b=-2? (3a^-2b^6/2a^-1b^5)^2

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0

Answer:

so lets just rewrite it with A=-3 amd B=-2

(-9^4^-9^2^5)^2

which is equal to... 1!

Hope This Helps!!!

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You can run 3­ 3/5 miles in 40 minutes. <br><br> What is your unit rate?
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Unit rate is how many units of work can you do in 1 unit of time

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(18/5mi)/40mins
divide by 40
aka times 1/40
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jenyasd209 [6]

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Step-by-step explanation:

3 0
3 years ago
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Use f(x)=(2x+1)/(3x-2) and g(x)=5x-1 to find <br> (gof)(x)
Orlov [11]

Answer:

From the functions f(x) and g(x) we have (g\circ f)(x)=\frac{7(x+1)}{3x-2}

Step-by-step explanation:

Given that the functions f is defined by f(x)=\frac{2x+1}{3x-2}

and g is g(x)=5x-1

To find the (g\circ f)(x) :

(g\circ f)(x)=g(f(x))

=g(\frac{2x+1}{3x-2})

=5(\frac{2x+1}{3x-2})-1

=\frac{10x+5}{3x-2}-1

=\frac{10x+5-1(3x-2)}{3x-2} ( by using the distributive property )

=\frac{10x+5-3x+2}{3x-2}

=\frac{7x+7}{3x-2} ( adding the like terms )

=\frac{7(x+1)}{3x-2}

Therefore (g\circ f)(x)=\frac{7(x+1)}{3x-2}.

5 0
3 years ago
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