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JulsSmile [24]
2 years ago
14

The straight line, Line L has an equation of 4x+y=7. Find the equation of the straight line perpendicular to Line L that passes

through (-8,3)
Mathematics
1 answer:
Jobisdone [24]2 years ago
3 0

Answer:

Step-by-step explanation:

y = -4x + 7

perp. 1/4

y - 3 = 1/4(x + 8)

y - 3 = 1/4x + 2

y = 1/4x + 5

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190mph

I used speed calculator with advanced mode

HTTP://www.omnicalculator.com/everyday-life/speed

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20 points show work pls im in a hurry
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Answer: since it doesnt say 620 is included , we can conclude that x>620, not x>=620 so the 8th week would be cut just short, so answer is 7

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fewer than 8 weeks

Step-by-step explanation:

1200-620=580

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2 years ago
A necklace that is originally 24.50 is on sale for 20% off.what is the sale price of the necklace?
bearhunter [10]

Answer: $19.60

Step-by-step explanation:

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$19.60 is the answer

7 0
2 years ago
Read 2 more answers
Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

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Ivenika [448]

Answer:

9/0

Step-by-step explanation:

6 0
3 years ago
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