What is the solution to the inequality X

A factory produces fuses, which are packaged in boxes of 22. Four fuses are selected at random from each box for inspection. The

mojhsa [17]

The probability of finding one of the two defective fuses is:
$\frac{2C1\times20C3}{22C4}=0.3117$
The probability of finding 2 defective fuses is: $\frac{2C2\times20C2}{22C4}=0.026$
Therefore the probability of rejecting is 0.3117 + 0.026 = 0.3377.

5 0

3 years ago

8 more questions! Please help, thanks

Allushta [10]

Problem 7 is choice B, which is the entire number line shaded in but the value -4 has a hole at this location to mean "exclude this point from the solution set". So basically x can be any number but -4.

Problem 8 is choice C. You have a closed circle (or filled in hole) at -1.5 on the number line. Then you shade to the left of the closed circle to indicate the set of values that are smaller than this endpoint. So n can be -1.5 or it can be smaller than -1.5 (something like -2 or -3, etc).

5 0

3 years ago

Hello I need help please this is due today

Zielflug [23.3K]

Answer:

angle6=angle8=71

Since no need step by step explanation, I'll just tell you the answer!

8 0

3 years ago

Read 2 more answers

Do political science classes require less writing than history classes? The 55 randomly selected political science classes assig

tia_tia [17]

Answer:

No, political science classes does not require less writing than history classes.

Step-by-step explanation:

We are given that the 55 randomly selected political science classes assigned an average of 19.6 pages of essay writing for the course. The standard deviation for these 55 classes was 4.8 pages.

The 50 randomly selected history classes assigned an average of 20.2 pages of essay writing for the course. The standard deviation for these 50 classes was 3.3 pages.

Let $\mu_1$ = mean writing required by political science classes

$\mu_2$ = mean writing required by history classes

SO, Null Hypothesis, $H_0$ : $\mu_1-\mu_2\geq0$ or $\mu_1\geq \mu_2$ {means that political science classes require more or equal writing than history classes}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2$ or $\mu_1$ {means that political science classes require less writing than history classes}

The test statistics that will be used here is Two-sample t test statistics as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1+_n__2-2$

where, $\bar X_1$ = sample average writing for political science course= 19.6 pages

$\bar X_2$ = sample average writing for history course= 20.2 pages

$s_1$ = sample standard deviation for political science classes = 4.8 pages

$s_2$ = sample standard deviation for history classes = 3.3 pages

$n_1$ = sample of selected political science classes = 55

$n_2$ = sample of selected history classes = 50

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(55-1)\times 4.8^{2}+(50-1)\times 3.3^{2} }{55+50-2} }$ = 4.154

So, the test statistics = $\frac{(19.6-20.2)-(0)}{4.154 \times \sqrt{\frac{1}{55}+\frac{1}{50} } }$ ~ $t_1_0_3$

= -0.739

Now at 0.01 significance level, the t table gives critical value of -2.367 at 103 degree of freedom for left-tailed test. Since our test statistics is more than the critical value of t as -0.739 > -2.367, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that political science classes require more or equal writing than history classes.

8 0

3 years ago

How did my teacher get 70?- like I don’t understand

Neporo4naja [7]

Answer:

Each triangle has angles and all of those angles add up to 180 degrees total. since both of those angles at the bottom are equal then their angles would each be 70.

3 0

2 years ago

Read 2 more answers

What is the solution to the inequality X - 5 > 15