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3 years ago

Factor out the greatest common factor. 30t2u + 12tu2 + 24tu

1 answer:

7 0

First you can combine 30tu^2 and 12tu^2 because they both have tu^2

So it would be 42tu^2 + 24tu

The answer is
6tu ( 7tu + 4 )

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How do I do this?<br>*Look at the directions in the photo*

lora16 [44]

Answer:

$Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2$

Step-by-step explanation:

$We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\$

$As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2$

$For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2$

$For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2$

$Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2$

7 0

2 years ago

What is the distance between (2,-1) and (2,5) rounded to the nearest 10th

xxMikexx [17]

Answer:

Step-by-step explanation:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(2-2)^2+(5+1)^2}=\sqrt{0^2+5^2}=\sqrt{25}=5$

5 0

3 years ago

Solve for x in simmilar triangles connected

amid [387]

Step-by-step explanation:

You can figure out the missing side length by using proportions because the corresponding side lengths form a proportion. Let's write ratios that form a proportion and find the pattern to figure out the length of the missing side. Looking at this you can see the pattern

6 0

2 years ago

(Refer to the attached image)

DENIUS [597]

<h3>Answer: 9 meters</h3>

===========================================

Work Shown:

side a = 8
side b = 5
angle C = 88 degrees

Applying the law of cosines

c^2 = a^2 + b^2 - 2*a*b*cos(C)

c^2 = 8^2 + 5^2 - 2*8*5*cos(88)

c^2 = 64 + 25 - 80*cos(88)

c^2 = 86.2080403

c = sqrt(86.2080403)

c = 9.2848285

c = 9

Technically he needs 10 meters of rope because of the extra 0.28 portion, but I'll stick with 9 meters since your teacher said to round to the nearest whole number.

5 0

1 year ago

How do I find the area. Please explain

olganol [36]

All you have to do is multiply it then you get the answer

7 0

3 years ago