The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X,
,
, False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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Answer:
m and k
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
f(x)=3 x-2
y= 3 x-2
x= 3y - 2
3 y -2 = x
3 y -2 + 2 = x + 2
<u>3 y </u> = <u>x </u> + <u>2</u>
3 3 3
<u>3 y </u> = <u>x </u> + <u>2 </u>
3 3 3
y = <u>x </u> + <u>2 </u> replace y with f ^ -1(x)
<em> </em> 3 3
f ^-1 (x) = <u>x</u> + <u>2 </u>
3 3