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3 years ago

Write a recursive rule for the sequence 4,10,16,22

Mathematics

1 answer:

Phantasy [73]3 years ago

8 0

Answer:

$a_{n+1}$ = $a_{n}$ + 6

Step-by-step explanation:

The terms have a common difference d between consecutive terms, that is

10 - 4 = 16 - 10 = 22 - 16 = 6

To obtain the next term add 6 to the previous term ( recursive rule ), thus

$a_{n+1}$ = $a_{n}$ + 6 with a₁ = 4

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Braiist can someome pls explain i dont know

Greeley [361]

Answer:

Step-by-step explanation:

Using the rule of exponents

$\frac{a^{m} }{a^{n} }$ = $a^{m-n}$

Consider the left side

$\frac{n^{x} }{n^{y} }$ = $n^{x-y}$ , then

$n^{x-y}$ = n²

Since bases on both sides are equal, equate the exponents

x - y = 2 → G

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3 years ago

S=L−rL solve for r Please solve this fast for much points.

podryga [215]

Subtract L from both sides.
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S−L=−rL
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3 years ago

Solve using the quadratic formula x^2-4x+1=0

sergiy2304 [10]

Answer:

x=2+ or - the square root of 3

Step-by-step explanation:

solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.

4 0

3 years ago

Read 2 more answers

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andrew-mc [135]

Answer:

1.63

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3 years ago

What equation represents the line that passes through points (1.-5) and (3 -17)?

zzz [600]

ALL LINES CAN BE REPRESENTED IN THE FORM $f(x) = ax+b$ .

We know that:

$f(1) = -5 \implies a\cdot(1)+b = -5 \implies a+b = -5$

and

$f(3) = -17 \implies a\cdot(3) +b = -17 \implies 3a+b = 17$

Observe that:

$3a+b = 2a+a+b = 2a+(a+b)$

So:

$2a+(a+b) =-17$

But we know that $a+b = -5$ , so:

$2a+(a+b) =-17$

$2a+(-5) = -17$

$2a = -12$

$a = -6$

Since:

$a+b = -5$

$(-6)+b = -5$

$b = 1$

So the line is:

$f(x) = 1-6x$

5 0

3 years ago