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Tema [17]
3 years ago
10

QoS services are protocols that allow routers to make decisions about which IP datagram may be more important than others. Which

IP header field would QoS details be found?
Computers and Technology
1 answer:
bekas [8.4K]3 years ago
4 0

Answer:

Type of service field

Explanation:

Data messages are transmitted in packets known as IP datagram. The IP datagram consist of header (which carries the header and control field) and payload (it carries the information).

The type of service field is an eight bit field carries information about the quality of service (QoS) features. The QoS allow routers to prioritize IP datagrams like which datagram is important than other datagram.

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Software designed specifically for managing real estate is an example of ________ software. Select one: A. e-commerce B. vertica
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The answer is "Option B"

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4 0
4 years ago
Problem: you need to write a code that read 2 array of size 10x10 of zero and ones that represent black
castortr0y [4]

Answer:

import java.util.Scanner;

import java.lang.*;

public class Main

{

       //variables declared static; to be used inside main()

       static int err;

    static int size=10;

    //arrays declared static; to be used inside main()

       static int[][] white = new int[size][size];

       static int[][] black = new int[size][size];        

   //method to recognize any errors in the image    

   static int recognition(int[][] img)

   {

       //variable to indicate any error

       int notImage=0;

       if(img[1][1]==0)

       {

           for(int l=0;l<size; l++)

           {

               for(int k=0;k<size; k++)

               {

                   if(img[l][k]!=0)

                       notImage++;

               }

           }

       }

       else

       {

           for(int l=0;l<size; l++)

           {

               for(int k=0;k<size; k++)

               {

                   if(img[l][k]!=1)

                       notImage++;

               }

           }

       }

       if(notImage!=0)

           return -1;

       else    

           return 0;

   }

public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);

 System.out.println("Enter the elements for 2d black array of size 10(enter 0): ");

 for(int l=0;l<size; l++)

       {

           for(int k=0; k<size; k++)

           {

               white[l][k]=sc.nextInt();    

           }

       }

 System.out.println("Enter the elements for 2d white array of size 10(enter 1): ");

 for(int l=0;l<size; l++)

       {

           for(int k=0; k<size; k++)

           {

               black[l][k]=sc.nextInt();    

           }

       }

 err = recognition(white);

 if(err==-1)

     System.out.println("White image has errors.");

 else    

     System.out.println("White image does not has errors.");

 

    err = recognition(black);

 if(err==-1)

     System.out.println("Black image has errors.");

 else    

     System.out.println("Black image does not has errors.");

}

}

OUTPUT

Program tested for smaller sizes.

Explanation:

1. Two two dimensional integer arrays are declared.

2. The variable size is declared and initialized to 10.

3. The main() prompts the user to enter the elements for both arrays; 1 for white and 0 for black.

4. Both the arrays are initialized inside two for loops independently.

5. These arrays are passed as parameter to the method, recognition(), one at a time.

6. Inside recognition(), an integer variable, notImage is declared and initialized to 0. If any other integer, other than 0 or 1 is encountered in the respective arrays, this variable is initialized to -1.

7. Inside main(), an integer variable, err, is declared. This variable stores the value returned by recognition().

8. Depending on the value of variable, err, message is displayed to the user appropriately.

3 0
3 years ago
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