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kozerog [31]
3 years ago
14

Describe the following graph. Use terms

Mathematics
1 answer:
timama [110]3 years ago
3 0
I think it’s non-linear
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Solve for x<br> Thanks in advance :)
uranmaximum [27]

Answer:

x = 25

Step-by-step explanation:

Here's my work. Basically, I knew that the x in angle A is alternate interior to angle C, so they would both be x. the 50 degrees is one a 180 degree line, so the inside of the triangle DCB is 130. X must equal x, so they would both be 25 degrees.

6 0
3 years ago
Please help me how to do no 5
snow_tiger [21]

Answer:

  -864

Step-by-step explanation:

The determinant of a matrix product is the product of the determinants. The determinant of a transpose is the same as the determinant of the original. Hence ...

  |AB^5C^T|=(4)(-2)^5(\frac{1}{4})=-32

The multiplication of an n×n matrix by a scalar 'a' multiplies its determinant by a^n, so the desired determinant is ...

  |3AB^5C^T|=3^3(-32) = \boxed{-864}

3 0
3 years ago
$280 is what percent of $3500?
professor190 [17]

Divide then multiply by 100:

280 / 3500 = 0.08

0.08 x 100 = 8%

Answer: 8%

6 0
2 years ago
Read 2 more answers
Q # 17 please solve the figures
Juliette [100K]
Answer: First option:
Angle C is congruent with angle X, angle D is congruent with angle Y, angle A is congruent with angle Z
6 0
3 years ago
Select the correct answer.
EleoNora [17]

Answer:

Option (B)

Step-by-step explanation:

There are two lines on the graph representing the system of equations.

First line passes through two points (-3, 1) and (-2, 3).

Slope of the line = \frac{y_2-y_1}{x_2-x_1}

                           = \frac{3-1}{-2+3}

                       m = 2

Equation of the line passing through (x', y') and slope = m is,

y - y' = m(x - x')

Equation of the line passing through (-3, 1) and slope = 2 will be,

y - 1 = 2(x + 3)

y = 2x + 7 ----------(1)

Second line passes through (0, 1) and (-1, 4) and y-intercept 'b' of the line is 1.

Let the equation of this line is,

y = mx + b

Slope 'm' = \frac{y_2-y_1}{x_2-x_1}

               = \frac{4-1}{-1-0}

               = -3

Here 'b' = 1

Therefore, equation of the line will be,

y = -3x + 1 ---------(2)

From equation (1) and (2),

2x + 7 = -3x + 1

5x = -6

x = -\frac{6}{5}

x = -1\frac{1}{5}

From equation (1),

y = 2x + 7

y = -\frac{12}{5}+7

  = \frac{-12+35}{5}

  = \frac{23}{5}

  = 4\frac{3}{5}

Therefore, exact solution of the system of equations is (-1\frac{1}{5},4\frac{3}{5}).

Option (B) will be the answer.

5 0
3 years ago
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