Answer:
y=2 is a line parallel to the x axis that passes through the point (0,2)
A line perpendicular to it would any line that is parallel to the y axis, which crosses the x axis at any point.
Step-by-step explanation:
Perpendicular lines are always found by reciprocating the negative value of the slope in question.
The slope in this case, in y = 2, is zero. You have a horizontal line hovering at the value “2” in the y-dimension, parallel to the x dimension. You can tell the slope is zero since there is no coefficient value paired with “x” so you can assume that since value multiplied by 0 is zero, the same instance has been performed in favor of a dearth of “x.”
Alright. So slope zero. The negative of zero is zero, since zero is neutral. It is neither positive nor negative (though some people tend to see it as positive for reasons irrelevant to your question. Will be answered at your request).
If you take the reciprocal of zero, it becomes undefined because what was once a numerator (0 divided by any number except 0, because then it would already be undefined) becomes a denominator (any numerator divided by 0 becomes undefined by default, as explained already). So now you can assume that the new line is undefined. This means that it is vertical! The only line that does not pass as a function. And it makes sense. A slope of 0 is 90° from a slope of no defined value, which will take on an unknown x-value since its location is not specified.
Answer:
7,13,
Step-by-step explanation:
that's just what I think
Answer:
31x^2-2 is the answer....
Step-by-step explanation:
+8y and -8y cross out.
So the first one is 3x=15
Second one is 2x=10
x=5
Then plug x is one of the equations
2(5)-8y=10
10-8y=10
x=5
y=0
