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3 years ago

If david must score 90 percent on his test in order to a if he scored a 89,90,98,86 what is the score on his fifth test

1 answer:

7 0

David's score on his fifth test would be an 87. If you add up all the scores from his first to his fourth test, it would 363. However, since there are five tests, in order to get a 90 percent, the sum of all five test scores would be 450. 450 - 363 = 87.

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Diano4ka-milaya [45]

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3 years ago

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3 years ago

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2 years ago

In Kailah's class the ratio of girls to boys is 13 to 8. If there were 16 boys, how many girls will there be?

VladimirAG [237]

Answer:

I believe that the answer is 26

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

Find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one

ziro4ka [17]

The probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

<h3>What is the probability?</h3>

Probability is synonymous with possibility. It is concerned with the occurrence of a random event.

Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.

No of failure,n = 7

No of trials,x≥6

A binomial probability is represented as;

$\rm P(x) = nC_x p^z(1-p)^{n-r}$

Substitute the given data;

$P(x \geq 6) = 7C_6 \times 9^6 \times 91-9)^{7-6} +7C_7 (9)^7+(1-9)^{(7-7)}$

$\rm P(x \geq 6) = 0.000000343311 \\\\ P(x \geq6)=0.000343311 \%$

Hence,the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

To learn more about probability, refer to the link: brainly.com/question/795909.

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4 0

2 years ago