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aev [14]
4 years ago
10

What is the solution to x+y=3

Mathematics
2 answers:
erastova [34]4 years ago
5 0
When x = 0 then y=3 point (0,3)
when y = 0 then x = 3 point (3,0)
opposite way round
when x=0 then 0-y=3 which means y = -3. point (0,-3)
when y=0 then x-0=3 which means y = 3. point (3,0)
draw a line going through points (0,3) and (3,0)
and a line going through points (0,-3) and point (3,0)


horsena [70]4 years ago
3 0
<span>Step 1. Intercepts occur when one of the coordinates is equal to 0. So the y-intercept occurs at x=0 and the x-intercept occurs at y=0. 

Step 2. It takes two points to make a line. So use these intercepts points 

Step 3. When x=0, then 0-y=3 or y=-3. So we have point (0,-3). 

Step 4. When y=0, then x-0=3 or x=3. So we have another point (3,0). 

Step 5. Graph the line as shown below using these two points found in Steps 3 and 4. 

 


Note x-y=3 can be written as y=x-3 in slope-intercept form where slope m=1 and y-intercept b=-3.</span>
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seraphim [82]
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3 years ago
What is the value of x in the figure above? Assume ↔B and ↔C are parallel.
Deffense [45]

Answer:

x=4

Step-by-step explanation:

180-58=26x+18

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4=x

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3 years ago
Need help with this problem for my cousin
yKpoI14uk [10]
You have separated the figure into three (3) parts. There are two squares (or rectangles on the bottom. Subtract 5 from 8 to find out the length of the side (right side). 8-5=3. Then subtract 3 from 8 (8-3=5). The new length is 5 ft. 5 multiplied by 5 is the area of one of the squares on the bottom (25 ft. squared). Multiply that by two to find the area of both the squares on the bottom (50 ft. squared).

There's also a rectangle on the top. The base is 15 ft. and the height is 3 ft. Remember that you subtracted 5 from 8 to find out the area of the two bottom squares. 15 multiplied by 3 is 45 (ft.)

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kari74 [83]

Answer:(a) BA = (-3,2)   (b) BC = (-9,6)

Step-by-step explanation: (a) Vector BA = position vector of B - position vector of A = vector OB - vector OA = (3-6) i + (4-2) j = -3i+2j [i, j are unit vectors along x and y-axis respectively]. Also vector BA=(-3,2).                     (b) Vector BC = position vector of B - position vector of C = vector OB - vector OC = (3-12) i + (4-(-2)) j = -9i+6j [i, j are unit vectors along x and y-axis respectively]. Also vector BA=(-9,6).

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