Find the prime fractorization of 96

Write (x+7)(x−2) as a sum

Dennis_Churaev [7]

Answer:

x^2+5x-14

Step-by-step explanation:

you multiply both equations so that you get:

x^2-2x+7x-14

and then you simplify it to:

x^2+5x-14

If you found this helpful please give it a thanks

I would also appreciate it if you give me a brainliest

8 0

3 years ago

The graph below shows Sean's distance, d, from his home (in kilometers) as a function of the time, t (in hours).

sdas [7]

Answer:

20

5

Step-by-step explanation:

4 0

2 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

PLEASE ANSWER QUICK A team is ordering sweatshirts and sweatpants for its players. Each sweatshirt costs $25 and each pair of s

tankabanditka [31]

Answer:

25x+ 21y

You multiply x by sweatshirts and y by sweatpants

Step-by-step explanation:

I don't know what sport your talking about or how many people are on the team so im not really sure but hete

7 0

3 years ago

-2 + 3b = 5b - 2(2b + 3) How do you solve for b?

mina [271]

-2 + 3b = 5b - 2(2b + 3) Distribute the -2 through the parentheses.
-2 + 3b = 5b - 4b - 6 Combine like terms
-2 + 3b = b - 6 Bring all "b's" to one side of the equation
-2 + 3b - b = b - b - 6 Combine like terms
-2 + 2b = -6 Bring the 2 to the right side of the equation
-2 + 2 + 2b = -6 + 2 Combine like terms
2b = -4 Isolate b by dividing both sides by 2
b = -4/2 = -2

Answer b = -2

6 0

3 years ago

Find the prime fractorization of 96​

Find the prime fractorization of 96