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olya-2409 [2.1K]
3 years ago
9

Find the prime fractorization of 96​

Mathematics
1 answer:
masha68 [24]3 years ago
7 0
Prime factorization: 96 = 2 x 2 x 2 x 2 x 2 x 3, which can also be written as 2⁵ x 3.
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Molly buys 2 boxes of crackers. Each box has 4 packages of crackers in it. Molly
castortr0y [4]

Answer:

4 x 2 x 10 = 80

Step-by-step explanation:

80 Crackers total divided evenly among the two boxes gives you 40 crackers per box. Next there are 4 packages and 40 crackers in the packages total. So divide 40 by 4. This gives you 10. 10 crackers per package.

5 0
3 years ago
Given the function f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
jeyben [28]

f(0) = 2(3)(0) = 0  ⇒  (0, 0)

f(1) = 2(3)(1) = 6  ⇒  (1, 6)

<u>rate of change from x = 0 to x = 1</u>

\frac{y2 - y1}{x2 - x1} = \frac{6 - 0}{1 - 0} = \frac{6}{1} = 6

******************************************

f(2) = 2(3)(2) = 12  ⇒  (2, 12)

f(3) = 2(3)(3) = 18  ⇒  (3, 18)

<u>rate of change from x = 2 to x = 3</u>

\frac{y2 - y1}{x2 - x1} = \frac{18 - 12}{3 - 2} = \frac{6}{1} = 6

*****************************************

Since it is the same line, they will have the same slope (aka rate of change).

5 0
4 years ago
8 decreased by the difference of t and 4
Zina [86]

Answer:

See below.

Step-by-step explanation:

(t-4)-8

Remove parenthesis.

t-4-8

Combine like terms.

t-12

-hope it helps

8 0
2 years ago
Tell whether the sentence below is true or false:
omeli [17]

Answer:

true

Step-by-step explanation:

geometry

3 0
3 years ago
Find the equation of the quadratic function with zeros -1 and 1 and a vertex at (0,-4)
Stolb23 [73]

The equation is f(x) = 4x^2 - 4.

You can find this by using an equation with parenthesis that equal each of the zeros.

f(x) = (x - 1)(x + 1)

Now, this equation will not give us the vertex that we're looking for. So, we must add a constant being multiplied to the front of it.

f(x) = c(x - 1)(x + 1)

Now we can find the constant by putting our vertex into the equation and solving.

f(x) = c(x - 1)(x + 1)

-4 = c(0 - 1)(0 + 1)

-4 = c(-1)(1)

-4 = -1c

c = 4

Now we put the c into the original equation and solve for standard form.

f(x) = 4(x - 1)(x + 1)

f(x) = 4(x^2 - 1)

f(x) = 4x^2 - 4

8 0
3 years ago
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