The correct answer to your question is B. Glycine-Tyrosine-Glycine-Histidine-Histidine.
You can find this by taking groups of codons starting with the first group (GGC). GGC is located under Glycine so Glycine will therfore be an amino acid found in the protein. Continue doing this with the next codons to come up with the answer.
I hope this isn't too late and still helps!
:)
1) Muscle Cell*myosin filament: changes shape and pulls on and releases actin filament allowing movement*If the myosin filament was missing or injured, it would be cause difficulty in movement2) Flagellum*Dynein arms: uses energy from ATP to "grab" the attached droplet allowing a wave like movement when pulling the droplets together* If the dynein arms was missing or injured the flagellum would have no possible way of moving causing it to stuck in mid-air
Answer:
A healthy artery is wider and has no blockages. The lumen (which is the hole in the centre of the artery), is open and clear. This means there is more blood flow. An artery of a person suffering from coronary heart disease is often blocked, usually by a fatty deposit. This means the blood does not flow as well. (See diagram, in which I would draw two arteries, one with a blockage of fatty deposit, one clear and healthy).
hope this helped you
please mark as the brainliest (ㆁωㆁ)
MRNA is ur answer hopefully
<span>F- allele for freckles
f- </span><span>allele without freckles
1) The man is heterozygote and has freckles, its indicating that the allele for freckles is dominant.
A cross between him and a woman who is also </span><span>heterozygote: Ff x Ff
it would result in the following probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
Their son would have a probability of 75% of being born with freckles.
2) The cross resulted in this probabilities:
</span><span><span>- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
So, the chance of being born heterozygote for this gene is 2/4, which is the same as half (50%).
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