<span>(5x^7 y^2)(-4x^4 y^5) =-20x^a y^b
</span><span>
solve this:
(5x^7 y^2)(-4x^4 y^5)
= -20 x^(7 + 4) y^(2 + 5)
= -20 x^11 y^7
answer
</span>A) a=11, b=7
Answer: rounded to the tens is 10 the tens place is the one in 12.81 or like the one in 13.81
Step-by-step explanation:
Answer:
-13
Step-by-step explanation:
Given are two vectors v and w.
v=(6,7,-3) and
w=(-7,5,2)
We are to find the dot product of v.w
We have
Dot product is obtained by multiplying corresponding pairs and adding them
Here we have
v.w=6(-7)+7(5)-3(2)
=-13
Number 6 the y intercept is 50 because that’s the point where it crosses the y axis and 7 I believe it would be D= 200
