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2 years ago

What is the missing angle measure of 112 68 50

Mathematics

2 answers:

IrinaK [193]2 years ago

6 0

I'm pretty sure it is 130

serious [3.7K]2 years ago

5 0

It's 130, any quadrilateral's angles add up to 360 and those numbers add up to 230, 360-230 = 130

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Yolanda is planning to put a pool in her backyard. The scaled model below gives the reduced measures for diameter and depth. Not

VMariaS [17]

Correct Answer:
C option: 6 feet

Solution:
Since Yolanda wants to keep the pool in proportion to the model, the ratio of diameter to depth of model and the pool will be same.

Let the depth of pool is x feet. So we can write:

Ratio of Diameter to Depth of Model = Ratio of Diameter to Depth of pool
 $18:4=27:x \\ \\ 
 \frac{18}{4} = \frac{27}{x} \\ \\ 
x=27* \frac{4}{18} \\ \\ 
x=6$

This means the depth of pool should be 6 feet if Yolanda wants to keep the pool in proportion to the model.

7 0

2 years ago

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All of used hard cover books at a yard sale are the same price Hugo paid 4.50 for 6 books explain how to find the unit price of

olga_2 [115]

Will they be 75p ?? Because you have £4.50÷6

8 0

1 year ago

Read 2 more answers

The Hawks are starting a babysitting business. They charge an initial deposit of $20

Ede4ka [16]

Answer:

Step-by-step explanation: So first you have to make this word problem into a equation into standard form so 20 is our (y) because that is the additional charge but our slope is 3 because that is what they charge per hr **when they say (per) usually the member with it is the slope** (sry I’m not the best explainer)

6 0

2 years ago

Ellus What is the measure of z? 4 16 z X Z = ✓ [?]

Sholpan [36]

Answer:

$z=\sqrt{80}$

Step-by-step explanation:

By geometric mean property:

$y= \sqrt {16\times 4}$

$y= \sqrt {64}$

$y= 8$

By Pythagoras Theorem:

$z=\sqrt{4^2 +8^2}$

$z=\sqrt{16 + 64}$

$z=\sqrt{80}$

8 0

2 years ago

If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

4 0

2 years ago