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3 years ago

Which of the following represents the sentence shown? “Twice a number, n, decreased by six is fourteen.”

1 answer:

8 0

Twice the number n will be expressed as 2n. So, that will be in our final answer. In order to decrease the number by 6, we will subtract 6. So there will be a - 6 in our final answer. Together, this is 2n - 6, and that is the same as the second option. So, the second option is the correct one.

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I need help with this problem

Anit [1.1K]

Answer:

show how you know .. :D good rhyme

Step-by-step explanation:

park = 4" x 6" ( inches) small park

but one inch = 30 miles ooh big park

4*30 X 6*30

120 X 180 miles... like a big game range? :? very big

since we only have 6 square inches to fit the map into... then.. what size of map would fit? what size equals 6 inches? 2 x 3 ? hmm yes that's 6

soooo shrink the 4" x 6" to 2"x 3" so the scale needs to double or

1 inch = 60 miles

2"*60 x 3"*60 = 120 x 180 miles.. looks good try that :)

6 0

3 years ago

Fill in the missing factor to show that 2/3 equivalent to 8/12.

Studentka2010 [4]

Answer:

4/4

Step-by-step explanation:

2/3 * what = 8/12

Multiply the top and bottom by 4/4

2/3 *4/4 = 8/12

3 0

2 years ago

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .