Write this into a equation

How many different anagrams can you make for the word MATHEMATICS?

Alex73 [517]

Answer:

4989600

Step-by-step explanation:

The given word is MATHEMATICS

Number of letters in the given word is 11

there are 2 M's, 2 A's and 2 T's

the given word is arranged in 11! ways

three letters are repeating, so we divide by repeating occurrences

number of different arrangements = $\frac{11!}{2!2!2!}$

= 4989600

7 0

3 years ago

Which statement is true? A. 2x – 1 = 13 and x = 6 B. 2x – 1 = 13 and x = 7 C. 2x + 1 = 13 and x = 7 D. 2x – 1 = 13 and x = 11

alexandr1967 [171]

Answer:

B. 2x – 1 = 13 and x = 7

Step-by-step explanation:

We are given 4 equations and a solution for each. We have to tell which of the given solution satisfies the given equation.

Option A.

2x -1 = 13 and x = 6

Using this value in the equation, we get:

2(6) -1 = 13

12 - 1 = 13

11 = 13, which is not true. Hence this option is not valid

Option B.

2x - 1 = 13 and x = 7

Using the value in the equation, we get:

2(7) - 1 =13

14 - 1 =13

13 = 13, which is true. Hence this option is valid.

Option C.

2x + 1 =13 and x = 7

Using the value in the equation, we get:

2(7) + 1 = 13

15 = 13, which is not true. So this option is not valid

Option D.

2x - 1 = 13 and x = 11

Using this value in the equation, we get:

2(11) - 1 = 13

21 = 13, which is not true. Hence this option is not valid.

6 0

3 years ago

According to the Census Bureau, 3.39 people reside in the typical American household. A sample of 26 households in Arizona retir

Vikki [24]

Answer:

$t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758$

$df=n-1=26-1=25$

$p_v =P(t_{(25)}$

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=2.73$ represent the sample mean

$s=1.22$ represent the sample standard deviation

$n=26$ sample size

$\mu_o =3.39$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is less than 3.39 persons, the system of hypothesis would be:

Null hypothesis: $\mu \geq 3.39$

Alternative hypothesis: $\mu < 3.39$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758$

P-value

The degreed of freedom are given by:

$df=n-1=26-1=25$

Since is a one sided lower test the p value would be:

$p_v =P(t_{(25)}$

Conclusion

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

3 0

3 years ago

263/4 plz answer thank you

mr_godi [17]

Answer:

65.75

Step-by-step explanation:

All you do is divide.

6 0

3 years ago

Read 2 more answers

Help! Prove the equality arccos √(2/3) - arccos (1+√6)/(2*√3) = π/6