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AnnyKZ [126]
3 years ago
9

During a class trip on the bus, the teacher in the row ahead of me silently asked me if I passed gas. Why did she whisper it wit

h a smile?
Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0

Answer:

She liked the smell and was turned on slightly.

Step-by-step explanation:

Some people get aroused when smelling a fart. The teacher was most likely trying to get into your pants.

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Cable has 24 pennies he has hafe as many nickels as pennies he has 5 more dimes than nickels he has 6 fewer quarters than dimes
Andreyy89
Pennies (P) = 24
Nickels = 1/2P
Dimes = 1/2P + 5
Quarters = (1/2P + 5) -6

Therefore...

Nickels = 1/2P = 1/2(24)= 12
Dimes = 12 + 5 = 17
Quarters = 17 - 6 = 11
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Quadrilateral ABCD is inscribed in this circle.
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180 °- 121°

= 59°

the answer is 59°
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Find the least common denominator for these two rational expressions. 3/2n -2/5n
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Every rational expression can be written in infinitely many equvialent  forms which is 3/3n-15/2.
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Which of the following represents the best way to calculate the area of the shaded region?
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2 years ago
Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the
igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:  

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

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Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

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