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3 years ago

Write the point slope form of the equation with the given characteristics:

Mathematics

1 answer:

KengaRu [80]3 years ago

3 0

Answer:

<u>point-slope form:</u> y - 0 = ½(x - 3)

Step-by-step explanation:

Given the slope, m = ½, and the x-intercept, (3, 0):

We can substitute these values into the point-slope form:

y - y1 = m(x - x1)

y - 0 = ½(x - 3) ← This is the point-slope form.

If ever you need to transform the point-slope form into its slope-intercept form, y = mx + b:

Distribute ½ into the parenthesis:

y - 0 = ½(x - 3)

y = ½x - 3/2 (this is the slope-intercept form).

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Hello,

let's follow the advise and proceed with the substitution

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with a and b real

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$y(x)=ae^{2ln(x)}+be^{-10ln(x)}=ax^2+bx^{-10}$

hope this helps

do not hesitate if you have any questions

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