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2 years ago

The Patriots won 9 games, lost 2 games, and tied 1 time. That means they won of their games!

Mathematics

2 answers:

aksik [14]2 years ago

8 0

Answer: Is this sopuse to be answered?

Step-by-step explanation:

???

RUDIKE [14]2 years ago

6 0

6 games they won eeeeee

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If segment DF is an angle bisector, solve for x

klasskru [66]

Answer:

x = 19

Step-by-step explanation:

Since DF is an angle bisector then it divides the opposite sides into segments that are proportional to the other 2 sides, that is

$\frac{DE}{DG}$ = $\frac{EF}{GF}$ , substitute values

$\frac{25}{22.5}$ = $\frac{x-9}{9}$ ( cross- multiply )

22.5(x - 9) = 225 ( divide both sides by 22.5 )

x - 9 = 10 ( add 9 to both sides )

x = 19

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2 years ago

Find x and y<br> (y+23)<br> (2x-17)

Viefleur [7K]

Answer:-2

Step-by-step explanation:

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3 years ago

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Write the number shown by 200+10+7

Natasha_Volkova [10]

The number would be 217

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3 years ago

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What is the equation of this line? y=−3/2x y=2/3x y=3/2x y=−2/3x Graph of a line passing through the origin and the point begin

iogann1982 [59]

Correct answer: y=(2/3)x

The line passes through the origin (0,0) and the pair (3,2)

the equation y=(2/3)x satisfies both points:

for (0,0): 0=(2/3)*0 = 0

for (3,2): 2 = (2/3)*3 = 2

and therefore is the correct linear function of the line described.

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3 years ago

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According to a study, 50 % of adult smokers started smoking before 21 years old. 5 smokers 21 years old or older are randomly se

belka [17]

Answer:

a) The probability that at least 2 of them started smoking before 21 years of age is 0.1875 = 18.75%.

b) The probability that at most 4 of them started smoking before 21 years of age is 0.96875 = 96.875%.

c) The probability that exactly 3 of them started smoking before 21 years of age is 0.3125 = 31.25%.

Step-by-step explanation:

For each smoker, there are only two possible outcomes. Either they started smoking before 21 years old, or they did not. Smokers are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of adult smokers started smoking before 21 years old.

This means that $p = 0.5$

5 smokers 21 years old or older are randomly selected, and the number of smokers who started smoking before 21 is recorded.

This means that $n = 5$ .

a) The probability that at least 2 of them started smoking before 21 years of age is

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125$

$P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.03125 + 0.15625 = 0.1875$

The probability that at least 2 of them started smoking before 21 years of age is 0.1875 = 18.75%.

b) The probability that at most 4 of them started smoking before 21 years of age is

This is:

$P(X \leq 4) = 1 - P(X = 5)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125$

$P(X \leq 4) = 1 - P(X = 5) = 1 - 0.03125 = 0.96875$

The probability that at most 4 of them started smoking before 21 years of age is 0.96875 = 96.875%.

c) The probability that exactly 3 of them started smoking before 21 years of age is

This is P(X = 3). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125$

The probability that exactly 3 of them started smoking before 21 years of age is 0.3125 = 31.25%.

4 0

2 years ago