Answer:
1st problem:
-1, 2i, -2i
Set the function equal to 0 and divide for x
0=x^3+x^2+4x+4
Subtract 4 from both sides leaving you with
-4=x^3+x^2+4x
divide both sides by four
-4÷4= -1
That is how you get -1
you now have -1=x^2+x^3+x
Solve for x buy finding the square roots of x^2, x^3 and subtracting x from both sides and you get 2i, -2i
Your answer to number one is -1, 2i, -2i
Second problem:
Find the LCD to be able to add these first
The LCD of (x-4)/x^2-2x is
x(x-2)
That is the first side done
The second side's LCD is (x+2)(x-2)
Now you can add the two together
x(x-2)+(x+2)(x-2)=
Your answer in fraction form is
(x+4)/x(x+2)
