Question

Two identical rubber balls from different heights. Ball 1 is dropped from a height of 159 feet , and ball 2 is dropped from a?height of 246 feet. Use the function f(t) = -16t^2 + h to determine the current height, f(t), of a ball dropped from a height h, over given time t.
When does ball 2 reach the ground? Round to the nearest hundredth. ​

Answer 1

Answer:

  after 3.92 seconds

Step-by-step explanation:

Fill in the given value of h to find the formula for the height of the ball. Then set the value of that height to zero and solve for t.

  $h_2(t)=-16t^2+246\\\\0=-16t^2+246\\\\0 = t^2-15.375 \quad\text{divide by -16}\\\\\sqrt{15.375}=t \quad\text{add 15.375, take the square root}\\\\t\approx 3.92$

Ball 2 reaches the ground after 3.92 seconds.