Chuck E Cheese charges for the number of hours you rent the party room and the number of

The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among

jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let X = number of households watching the show.

The probability of the random variable x is, P (X) = p = 0.18.

The sample selected for the survey is of size, n = 14

The random variable X follows a Binomial distribution with parameter n = 14 and p = 0.18.

The probability of a Binomial distribution is computed using the formula:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...$

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

$P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062$

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-0.062\\=0.938$

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

$={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253$

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0

3 years ago

3x - 6 less than or equal to -3 on a graph

g100num [7]

I believe that -3 is less than 3x-6 because if you look at their graph -3’s graph is below 3x-6 graph

4 0

3 years ago

2x-7=13 what is does x stand for?

andriy [413]

Answer:

x=10

Step-by-step explanation:

2x-7=13

13+7=20

20/2=10

lets see if it works:

2(10)-7-13

20-7=13

it works! which means is 10

please mark me as brainliest!!<3

7 0

3 years ago

b is the midpoint of AC and E is the midpoint of BD if A(-9,-4) C(-1,6) and E(-4,-3) find the coirdinates of D

natima [27]

To find the coordinate of the point D, we can use the Midpoint point of a line Segment formula. Calculation of the formula are as follows,

Given two points A(x1,y1) and C(x2,y2), we need to locate the midpoint coordinate of this line denoted as B(x,y).

To solve for the value of x and y, we get,

x=(x1+x2)/2 and y=(y1+y2)/2

For the given problem, we need to solve first the midpoint coordinate of AC which is B.

So, A(-9,-4)=A(x1,y1) and C(-1,6)=C(x2,y2)

Hence,

B(x,y)=B((-9+(-1))/2, (-4+6)/2)=B(-10/2,2/2)=B(-5,1)

Now, since the midpoint is given but one point in the line is missing. To solve for the missing point D(x2,y2), we need to use the Midpoint Segment Formula.

That is, B(-5,1)=B(x,y) and E(-4,-3)=E(x1,y1)

So,

x=(x1+x2)/2 and y=(y1+y2)/2

-5=(-4+x2)/2 and 1=(-3+y2)/2

By Cross Multiplication and Transposing method,

-5(2)=-4+x2 and 1(2)=-3+y2

x2=-10+4=-6 and y2=3+2=5

Thus, the coordinate of D is D(-6,5).

5 0

3 years ago

Two college instructors are interested in whether or not there is any variation in the way they grade math exams. They each grad

AlekseyPX

Answer:

Since the calculated value of F = 1.4397 is less than the critical value of

F (9,9)= 2.4403 we conclude that the first instructor's variance is smaller and reject H0.

Step-by-step explanation:

1)Formulate the hypothesis that first variance is equal or greater than the second variance

H0: σ₁²≥σ₂² against the claim that the first instructor's variance is smaller

Ha: σ₁²< σ₂²

2) Test Statistic F= s₂²/s₁²

F= 84.8/ 58.9= 1.4397

3)Degrees of Freedom = n1-1= 10-1= 9 and n2 = 10-1= 9

4)Critical value at 10 % significance level= F(9,9)= 2.4403

5)Since the calculated value of F = 1.4397 is less than the critical value of

F (9,9)= 2.4403 we conclude that the first instructor's variance is smaller and reject H0.

4 0

3 years ago