Answer:
y =10
Step-by-step explanation:
The equation of a line in point slope form is expressed as;
y - y0 = m(x-x0)
m is the slope
(x0, y0) is the point on the line
Given
m = 0 and (x0, y0) = (4, 10)
On substituting;
y - 10 = 0(x-4)
y - 10 = 0
y = 0+10
y = 10
Hence the required equation of the line is y =10
You need to move the decimal point to be at 1.
Since this is a decimal, the power will be negative.
I had to move the decimal 6 places.
So,
1^-6
I hope this helps!
~kaikers
Answer:
2x^2+4x-16
Step-by-step explanation:
The quadratic can be written as
f(x) = a(x-z1)(x-z2) where z1 and z2 are the roots
f(x) = a (x-2)(x- -4)
a is the leading coefficient
f(x) = 2(x-2)(x+4)
= 2(x^2 -2x+4x-8)
= 2(x^2 +2x-8)
= 2x^2 +4x-16
I get it now!!!!
After some reasearch, I believe the answer is ~q --> p
Can I get brainliest answer pls????
