I believe A is the best. You might get addicted to the meds and get hurt somehow.
Answer:
(A)The area of the square is greater than the area of the rectangle.
(C)The value of x must be greater than 4
(E)The area of the rectangle is 
Step-by-step explanation:
The Square has side lengths of (x - 2) units.
Area of the Square

The rectangle has a length of x units and a width of (x - 4) units.
Area of the Rectangle =
<u>The following statements are true:</u>
(A)The area of the square is greater than the area of the rectangle.
This is because the area of the square is an addition of 4 to the area of the rectangle.
(C)The value of x must be greater than 4
If x is less than or equal to 4, the area of the rectangle will be negative or zero.
(E)The area of the rectangle is 
Dividing by 2, we have S/2=lw+lh+wh. After that, we subtract lh from both sides to get S/2-lh=lw+wh. Next, we divide both sides by w to get (S/2)/w=l+h. Next, we divide by S/2 to get 1/w=(l+h)/(S/2). Lastly, we multiply by w and divide by (l+h)/(S/2) to get w=(S/2)/(l+h)
a. Answer: D: (∞, ∞)
R: (-∞, ∞)
<u>Step-by-step explanation:</u>
Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).
Theoretical range is the range of the equation given the domain.
c(p) = 25p
There are no restrictions on the p so the theoretical domain is All Real Numbers.
Multiplying 25 by All Real Numbers results in the range being All Real Numbers.
a) D: (∞, ∞)
R: (-∞, ∞)
*********************************************************************************
b. Answer: D: (0, 200)
R: (0, 5000)
<u>Step-by-step explanation:</u>
Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.
Practical range is the range of the equation given the practical values of the domain.
The problem states that p represents the number of cups. Since we can't have a negative amount of cups, p ≥ 0. The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200
The range is 25p → (25)0 ≤ (25)p ≤ (25)200
→ 0 ≤ 25p ≤ 5000
b) D: (0, 200)
R: (0, 5000)