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3 years ago

15

Are the triangles below similar? How do you know? Select one: a. yes, by AA~ b. yes, by SSS~ c. no d. yes, by SAS~ Have a good d

ay

1 answer:

Gemiola [76]3 years ago

8 0

Answer:

Yes, they are similar by SSS.

Step-by-step explanation:

You can see that the triangles have proportional sides. 12/8 = 1.5, 7.5/5 = 1.5. Since the sides have the same ratios, these triangles are similar!

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Is –2,823,680 − 8,957,599 positive or negative?

Scrat [10]

Answer:

negative

Step-by-step explanation: it has negative signs

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3 years ago

Read 2 more answers

Hello ! I need a solution for this exercise: either 1≤x≤2 and let A = -3 + 8 / (x + 1) -2x² Show that -9≤A≤-1

Phantasy [73]

\left[A \right] = \left[ \frac{ - \left( 5 - 3\,x - 2\,x^{2} - 2\,x^{3}\right) }{-1-x}\right][A]=[−1−x−(5−3x−2x2−2x3)] I hope helping this answer

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3 years ago

CAN SOMEONE HELP:) PLSSS

rewona [7]

Answer:

I honestly don’t know I am gonna guess

Step-by-step explanation:

1/12?

. 。 • 　ﾟ。　. .

　. . 　。。　. .

. 。 ඞ 。 . • 　• .

.

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Have a nice day UwU

6 0

3 years ago

Evaluate the spherical coordinate integral

expeople1 [14]

Rewrite the equations of the given boundary lines:

<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1

<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4

<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2

<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5

This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.

Compute the Jacobian determinant for this change of coordinates:

$J=\begin{bmatrix}\frac{\partial u}{\partial x}&\frac{\partial u}{\partial y}\\\frac{\partial v}{\partial x}&\frac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&1\\-2&1\end{bmatrix}\implies|\det J|=3$

Rewrite the integrand:

$-3x+4y=-3\cdot\dfrac{u-v}3+4\cdot\dfrac{2u+v}3=\dfrac{5u+7v}3$

The integral is then

$\displaystyle\iint_R(-3x+4y)\,\mathrm dx\,\mathrm dy=3\iint_{R'}\frac{5u+7v}3\,\mathrm du\,\mathrm dv=\int_2^5\int_1^45u+7v\,\mathrm du\,\mathrm dv=\boxed{333}$

5 0

3 years ago

Which table identifies the one-sided and two-sided limits of function at x = 2?

Yuliya22 [10]

Answer:

Table 3

Step-by-step explanation:

Check table three;

$lim\:_{x\to \:2^-}\:f\left(x\right)=\:4$

$lim\:_{x\to \:2^+}\:f\left(x\right)=\:1$

Since the left hand limit $(lim\:_{x\to \:2^-}\:f\left(x\right))$ is not equal to the right hand limit $(lim\:_{x\to \:2^+}\:f\left(x\right))$ , the limit as x approaches to 2 does not exist.

Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2

6 0

3 years ago