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Greeley [361]
4 years ago
8

How do I solve this problem using the Midpoint Formula?

Mathematics
1 answer:
wlad13 [49]4 years ago
5 0

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5-4}{2}~~,~~\cfrac{-6+0}{2} \right)\implies \left( \cfrac{1}{2}~~,~~\cfrac{-6}{2} \right)\implies \left(\frac{1}{2}~,~-3 \right)

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In Trigonometey, the radian measure of an angle theta is the length of an arc that subtends in a circle of radius having a formula of circumeference divided by 2xpi and that the ratio 2pi and the circumference over the radius is called tha radian measure.
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1. Marie deposits $125 in a savings account
slava [35]

Answer:

Step-by-step explanation:

The formula for simple interest is

I = Prt

where I is the interest earned, P is the initial deposit, r is the rate in decimal form, and t is the time in years.  For us,

I = 125(.03)(3) which gives us an interest amount of

I = 11.25

To find out how much money she has total after that interest builds up, we add that interest amount to the initial investement amount to get

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Answer:

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4 years ago
What is the area, in square centimeters, of the shape below? 3.7 cm 5.8 cm​
Fudgin [204]

Answer:

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3 0
3 years ago
Directions: for questions 1 through 4, find the diagonal length of each solid figure.
Alex787 [66]
\text{The length of the diagonal is }11.2\text{ mm}

Here, we want to find the diagonal of the given solid

To do this, we need the appropriate triangle

Firstly, we need the diagonal of the base

To get this, we use Pythagoras' theorem for the base

The other measures are 6 mm and 8 mm

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Let us have the diagonal as l

Mathematically;

\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}

Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above

Thus, we calculate this using the Pytthagoras' theorem as follows;

\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}

7 0
1 year ago
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