How many terms does this expression have? 6a+4b-7 4 2 1 3

Please Help

xxMikexx [17]

Answer:

degree of length = 1

degree of width = 1

degree of height = 3

degree of volume = 4

Step-by-step explanation:

V = (4x - 1)( x)(x³) = (4x² - x)x³ = 4x∧5 - x∧4

dV/dx = 20x∧4 - 4x³

d²V/dx² = 80x³ - 12x²

80x³ - 12x² = 0

4x²(20x - 3) = 0

20x - 3 = 0

20x = 3

∴ x = 3/20

Length, 4x - 1 = 4 (3/20) - 1 = 3/5 - 1 = -2/5

∴ degree of length = 1

Width, x = 3/20

∴ degree of width = 1

Height, x³ = (3/20)³ = 27/8000

∴ degree of height = 3

Volume, 4x∧5 - x∧4 = 4(3/20)∧5 - (3/20)∧4 = 4(243/3200000) - (81/160000) = 243/800000 - 81/160000 = (243 - 405)/800000 = - 162/800000 = - 81/400000

∴ degree of volume = 4

5 0

3 years ago

Read 2 more answers

Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne

Pavlova-9 [17]

Answer:

$t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507$

$p_v =P(t_{(15)}>1.507)=0.076$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X_{CTS}=2.35$ represent the mean for the sample CTS

$\bar X_{N}=1.83$ represent the mean for the sample Normal

$s_{CTS}=0.88$ represent the sample standard deviation for the sample of CTS

$s_{N}=0.54$ represent the sample standard deviation for the sample of Normal

$n_{CTS}=10$ sample size selected for the CTS

$n_{N}=7$ sample size selected for the Normal

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the group CTS is higher than the mean for the Normal, the system of hypothesis would be:

Null hypothesis: $\mu_{CTS} \leq \mu_{N}$

Alternative hypothesis: $\mu_{CTS} > \mu_{N}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{CTS}-\bar X_{N}}{\sqrt{\frac{s^2_{CTS}}{n_{CTS}}+\frac{s^2_{N}}{n_{N}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{CTS}+n_{N}-2=10+7-2=15$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(15)}>1.507)=0.076$

We can use the following excel code to calculate the p value in Excel:"=1-T.DIST(1.507,15,TRUE)"

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

6 0

4 years ago

at 2 P.M the level of the water in the pool was 10 feet. At 6 P.M the level of water was 2 feet. Find the constant rate of chang

Anna35 [415]

Decreases by 2ft every hour

3 0

4 years ago

Which graph is a function of x?

motikmotik

Answer:

Can i see the graphs?

Step-by-step explanation:

3 0

4 years ago

If ∠1 and ∠2 are vertical angles and m∠2 = 108°, find m∠1.

oee [108]

Answer:

angle 1 = 108°

Step-by-step explanation:

because angle 1 and angle 2 are vertical angles and vertical angles are equal.

6 0

3 years ago