Answer:
The percentage of cockroaches weighing between 77 grams and 83 grams is about 55%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The percentage of cockroaches weighing between 77 grams and 83 grams
This is the pvalue of Z when X = 83 subtracted by the pvalue of Z when X = 83. So
X = 83



has a pvalue of 0.7734
X = 77



has a pvalue of 0.2266
0.7734 - 0.2266 = 0.5468
Rounded to the nearest whole number, 55%
The percentage of cockroaches weighing between 77 grams and 83 grams is about 55%.
The two variables present here would be the value of the car, and the time is depreciates for. Time is the independent variable, because it is not affected by the value of car. Since the value of the car is a function of the time, therefore, it is the dependent variable.
The answer to the first question would be 1% of the purchase price and the answer to the second question would be 0.5 % of the purchase price.
Answer:
1.180
2.50
3.56
Step-by-step explanation:
M<4,M<2 and M<5 have to add up to 180 as a result of being a parallel line.
Making m<2 50 since 46°+84=130, 180-130=50.
Since m<1 is 74 and knowing m<2 is 50 74+50=124 180-124=56 m<3=56
Therefore 1,2,3 =180°
X=2y+11 and 4x+3y=11 so choose one of them. I choose x=2y+11 and solve it like this 4(2y+11)+3y=11
8y+44+3y=11
11y=-33
y=-3