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GenaCL600 [577]
3 years ago
5

Do the lines y=5x+2 and y=5x+4 intersect? if so, at what point? Thanks for your help!!

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0
They do not intersect, they are parallel lines. 
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What is the rate of change for the graph shown below?
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Answer:

-3/4

Step-by-step explanation:

the rate of change is the slope of the line

7-3/0-(-4) = -3/4

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Determine the intervals on which the function is increasing, decreasing, and constant. (5 points)
TEA [102]
The one above the one you have now
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What is the a-value of the function, then determine if the graph opening up or down f(x)=−5(x+7)2+6?
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We know that
the equation of the vertical parabola in the vertex form is
<span>y=a(x-h)²+k
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in this problem  we have
f(x)=−5(x+7)²<span>+6
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see the attached figure

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Josephine has a rectangular garden with an area of 2x2
sergeinik [125]

Answer:

Fourth example, (2x - 3) and (x + 2), are possible dimensions

Step-by-step explanation:

Let's go through all the responses one by one;

First of all the area of the rectangular garden can be computed through length times width, such that:

(x^2 - 3) * (2) = 2x^2 + x - 6,

(2x + 3) * (x-2) = 2x^2 + x - 6,

(2x + 2) * (x-3) = 2x^2 + x - 6,

(2x - 3) * (x + 2) = 2x^2 + x - 6

Now in each of these examples, it should be that the products are equivalent to the area according to the length by width rule, so let's see which is truly the correct dimensions by justifying whether the product is truly equivalent to the area.

First example:

2 * (x^2 - 3) = 2x^2 - 6

Now 2x^2 - 6 ≠ 2x^2 + x - 6 so the first example is not a possibility,

Second example:

(2x + 3) * (x-2) = 2x^2- x - 6

Now 2x^2- x - 6 ≠ 2x^2 + x - 6 so the second example is not a possibility,

Third example:

(2x + 2) * (x-3) = 2x^2 - 4x - 6

Now 2x^2 - 4x - 6 ≠ 2x^2 + x - 6 so the third example is not a possibility,

Fourth example:

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Here 2x^2 + x - 6 = 2x^2 + x - 6 so the fourth example can act as possible dimensions

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3 years ago
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