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4 years ago

Noah solved an equation as shown below and found that the equation has infinitely many solutions.

Mathematics

2 answers:

Mars2501 [29]4 years ago

6 0

ANSWER

A. Noah is correct because the two sides of the equation are equivalent expressions.

EXPLANATION

The equation given to Noah was

$-3(x + 4) + 2x = 2(x - 6) - 3x$

He expanded to get:

$-3x - 12 + 2x = 2x - 12 - 3x$

He then further simplified each side of the equation to get;

$-x - 12 = -x - 12$

Both sides of this equation are equivalent.

Therefore the equation has infinitely many solutions.

The correct answer is A

Anestetic [448]4 years ago

3 0

Answer:

Option A) Noah is correct because the two sides of the equation are equivalent expressions.

Step-by-step explanation:

We are given the following information in the question:

$-3(x + 4) + 2x = 2(x - 6) - 3x\\-3x - 12 + 2x = 2x - 12 - 3x\\-x - 12 = -x - 12$

The above equation has infinitely many solutions.

Infinite solution:

If an equation end up with equal values on each side of the equation, then there are infinite solution as for all the values of x the equations would be satisfied.

Noah is correct.

Option A) Noah is correct because the two sides of the equation are equivalent expressions.

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The better option will be at DiscountsRUs 40% off on any purchase.

<h3>What is the discount?</h3>

The amount of money which is reduced on any product below its actual selling price is called the discount.

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2 years ago

Identify the parent function that can be used to graph the function f(x)= (1/4 x)^3

Kaylis [27]

Answer:

$f(x)=x^3$

Step-by-step explanation:

The parent function denotes the simplest function (free from any horizontal/vertical stretch/compression) that represents a family of functions. In this case the term 1/4 indicates a horizontal stretch and should be removed to find the parent function of $f(x)=x^3$ . From here we're in simplest form, since $y=x$ or others represent a completely different family of functions and cannot be obtained from horizontal/vertical stretches/compressions.